Basic Motion Graphs (velocity-time)

  • Thread starter Thread starter PolyFX
  • Start date Start date
  • Tags Tags
    Graphs Motion
Click For Summary
SUMMARY

The discussion centers on calculating the average net force acting on a ping-pong ball with a mass of 0.0027 kg over a time interval from 12.35 s to 14.35 s, considering air resistance and wind. The user attempts to apply the formula Fnet = P/t, where P is momentum, but encounters difficulties in obtaining the correct answer. Key equations referenced include Fnet = -mg and the relationship between displacement, velocity, and momentum.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with momentum calculations
  • Knowledge of vector subtraction for displacement
  • Basic grasp of kinematics and forces in physics
NEXT STEPS
  • Review the concept of momentum and its relation to net force
  • Learn about the effects of air resistance on projectile motion
  • Study the derivation and application of Fnet = P/t in various scenarios
  • Explore vector analysis for calculating displacement and velocity
USEFUL FOR

Students studying physics, particularly those focusing on dynamics and kinematics, as well as educators looking for examples of force calculations in real-world scenarios.

PolyFX
Messages
30
Reaction score
0
Momentum & Net Force Question

Okay, so I got the previous question I asked and I had another new question to ask so rather than make a new topic and seem like I'm spamming the forums, I just decided to edit my original post. I just hope no one replies to my old post while I'm writing this one!

Homework Statement


A ping-pong ball whose mass is 0.0027 kg (2.7 g) is acted upon by the Earth and the air (there is air resistance, and there is also a strong wind). This table gives the position of the ball at several times:
Time Position

12.35 s < 3.17, 2.54, -9.38 > m
12.39 s < 3.25, 2.50, -9.40 > m
... ...
14.35 s < 10.17, -1.16, -10.40 > m
14.39 s < 10.37, -1.27, -10.42 > m


In the time interval from 12.35 s to 14.35 s, what was the average net force acting on the ball?

Homework Equations


Fnet = P/t where p is momentum and t is time interval
Fnet = -mg

The Attempt at a Solution



First I get the displacement by subracting the final position vector - initial position vector. I then divide that vector by the time interval (2 seconds) to get the average velocity. I use the formula p = mv to find the momentum.

I rearrange the formula p = fnet( t ) to isolate for fnet
so fnet = p/t.

However, with this method I do not get the right answer.
 
Last edited:
Physics news on Phys.org
Okay, so I got the previous question I asked and I had another new question to ask so rather than make a new topic and seem like I'm spamming the forums, I just decided to edit my original post. I just hope no one replies to my old post while I'm writing this one!
 

Similar threads

Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
9K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K