Velocity-time graph given. Plot acceleration vs time etc.

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SUMMARY

The discussion revolves around the calculation of acceleration from a velocity-time graph as outlined in Serway Physics Section 2.4. Participants confirm that the average acceleration can be accurately determined for specified time intervals: from t=5.00 s to t=15.0 s and from t=0 to t=20.0 s. The consensus is that the calculations presented are correct, affirming the methodology used in deriving acceleration from the given graph.

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  • Understanding of velocity-time graphs
  • Knowledge of basic kinematics
  • Familiarity with average acceleration calculations
  • Proficiency in interpreting graphical data
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  • Study the principles of kinematics in Serway Physics
  • Learn how to derive acceleration from velocity-time graphs
  • Practice plotting acceleration versus time for various motion scenarios
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Students studying physics, particularly those focusing on kinematics and acceleration calculations, as well as educators looking for examples of velocity-time graph analysis.

Alexanddros81
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Homework Statement


Serway Physics Section 2.4 Acceleration

15. A velocity-time graph for an object moving along the x-axis is shown in Figure P2.15.
(a) Plot a graph of the acceleration versus time. Determine the average acceleration of
the object (b) in the time interval t=5.00 s to t=15.0 s and (c) in the time interval t=0 to t = 20.0 s.

Homework Equations


Serway Physics Figure P2_15.jpg


The Attempt at a Solution



Serway Physics 2_15001.jpg

[/B]
Is my calculation correct?
 

Attachments

  • Serway Physics Figure P2_15.jpg
    Serway Physics Figure P2_15.jpg
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  • Serway Physics 2_15001.jpg
    Serway Physics 2_15001.jpg
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Alexanddros81 said:

Homework Statement


Serway Physics Section 2.4 Acceleration

15. A velocity-time graph for an object moving along the x-axis is shown in Figure P2.15.
(a) Plot a graph of the acceleration versus time. Determine the average acceleration of
the object (b) in the time interval t=5.00 s to t=15.0 s and (c) in the time interval t=0 to t = 20.0 s.

Homework Equations


View attachment 233466

The Attempt at a Solution



View attachment 233467
[/B]
Is my calculation correct?
It is correct.
 

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