Basic Motion Graphs (velocity-time)

  • Thread starter Thread starter PolyFX
  • Start date Start date
  • Tags Tags
    Graphs Motion
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 3K views
PolyFX
Messages
30
Reaction score
0
Momentum & Net Force Question

Okay, so I got the previous question I asked and I had another new question to ask so rather than make a new topic and seem like I'm spamming the forums, I just decided to edit my original post. I just hope no one replies to my old post while I'm writing this one!

Homework Statement


A ping-pong ball whose mass is 0.0027 kg (2.7 g) is acted upon by the Earth and the air (there is air resistance, and there is also a strong wind). This table gives the position of the ball at several times:
Time Position

12.35 s < 3.17, 2.54, -9.38 > m
12.39 s < 3.25, 2.50, -9.40 > m
... ...
14.35 s < 10.17, -1.16, -10.40 > m
14.39 s < 10.37, -1.27, -10.42 > m


In the time interval from 12.35 s to 14.35 s, what was the average net force acting on the ball?

Homework Equations


Fnet = P/t where p is momentum and t is time interval
Fnet = -mg

The Attempt at a Solution



First I get the displacement by subracting the final position vector - initial position vector. I then divide that vector by the time interval (2 seconds) to get the average velocity. I use the formula p = mv to find the momentum.

I rearrange the formula p = fnet( t ) to isolate for fnet
so fnet = p/t.

However, with this method I do not get the right answer.
 
Last edited:
Physics news on Phys.org
Okay, so I got the previous question I asked and I had another new question to ask so rather than make a new topic and seem like I'm spamming the forums, I just decided to edit my original post. I just hope no one replies to my old post while I'm writing this one!