Basic Quantum Physics - Particle(s) in a (3D) Box

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Homework Help Overview

The problem involves a system of 20 neutrons confined in a three-dimensional box with specified dimensions. The task is to determine the total kinetic energy of the system, given that each eigenstate can accommodate two neutrons due to their spin states.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the interpretation of the energy equation provided and question its application to the total energy of the system. There is uncertainty about the implications of the Pauli exclusion principle and how it affects the selection of quantum states for the neutrons. Some participants suggest calculating the sum of the lowest energy states while considering the occupancy of each state.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and the implications of temperature on the state of the system. Guidance has been offered regarding the Pauli exclusion principle and the need to identify the correct permutations of quantum numbers to find the lowest energy states.

Contextual Notes

There is a mention of the assumption that the system could be at absolute zero temperature, which would influence the occupancy of energy states. Additionally, the energy expression's prefactor suggests a high temperature, leading to further discussion about the system's ground state versus excited states.

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Homework Statement


A system of 20 neutrons are confined in the region

[tex]0<x<3L[/tex]
[tex]0<y<L[/tex]
[tex]0<z<2L[/tex]

With [tex]L=10^{-15}m[/tex]

If each eigenstate can accept 2 neutrons (corresponding to the 2 possible spin states) what is the total kinetic energy of the system?

Homework Equations



I found the total energy to be
[tex]E = \frac{\pi^{2}\overline{h}^{2}}{2mL^{2}}\left(\frac{(n_{1})^{2}}{9}+(n_{2})^{2}+\frac{(n_{3})^{2}}{4}\right)[/tex]

The Attempt at a Solution



Now, I do not really understand what the question is asking.
But my current idea is to do trial and error for a combination of ns that gives the same energy and multiply it by 20.

Is this right?

Thanks in advance
 
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In "relevant equations", the energy expression you have ain't for the total energy, but rather for the energy one particle, given its n1, n2, n3 state.

What do you know about the Pauli exclusion principle?
 
Hi bjnartowt,

I honestly don't know about the principle.
By the sound of it and after looking quickly at wikipedia, my understanding is that in this case, no three or more neutrons can have the same combination of ns (since each eigenstate can accept 2 neutrons).

So I'm guessing that the question is asking for the sum of the lowest 10 energies i.e. at (n1,n2,n3 = 1,1,1
n1,n2,n3 = 2,1,1
n1,n2,n3 = 1,1,2
n1,n2,n3 = 3,1,1 and so on)
and multiply it by 2?
 
v_bachtiar said:
Hi bjnartowt,

I honestly don't know about the principle.
By the sound of it and after looking quickly at wikipedia, my understanding is that in this case, no three or more neutrons can have the same combination of ns (since each eigenstate can accept 2 neutrons).

So I'm guessing that the question is asking for the sum of the lowest 10 energies i.e. at (n1,n2,n3 = 1,1,1
n1,n2,n3 = 2,1,1
n1,n2,n3 = 1,1,2
n1,n2,n3 = 3,1,1 and so on)
and multiply it by 2?

Are you saying that only three neutrons are allowed to have the same permutation of "n"-values?
 
I'm saying that only two neutrons can have the same permutation (combination) of n-values.
 
v_bachtiar said:
I'm saying that only two neutrons can have the same permutation (combination) of n-values.

Excellent: then you understand Pauli exclusion.

Perhaps the path to the answer is a little clearer?
 
I do not know which permutations of n-values to choose though.

My guess is that the question is asking for the sum of the lowest 10 energies, so choose 10 permutations of n-values giving the lowest energies and sum them up. Then times this sum by 2 since each energy is occupied by 2 neutrons.

Would this be right?
 
You know what, I don't know which permutations of n-values to choose through either...unless someone told me "Hey, this box of 20 neutrons is at absolute-zero temperature". Then, I *think* you'd start from two neutrons in 001, two in 010, two in 100, two in 002, two in 012, etc. which I think is obeying Pauli-exclusion.

I think that in general, if your temperature was "T", you'd use the Fermi-Dirac distribution.

So yeah...I think I'm steering us in the right direction, but I flub little details. I hope someone else posts too.
 
bjnartowt brings up a good point, that if the system is at a nonzero temperature, some of the neutrons could be excited into higher energy levels. If this is for a statistical mechanics class, then that might be the intent of the problem. But if it's just a regular quantum mechanics class, I would guess that you're supposed to assume the system is in its ground state.

By the way, be careful to actually figure out which energy levels are the lowest ones. Don't just assume that 001, 010, 100, etc. are in order of increasing energy.
 
  • #10
diazona said:
bjnartowt brings up a good point, that if the system is at a nonzero temperature, some of the neutrons could be excited into higher energy levels. If this is for a statistical mechanics class, then that might be the intent of the problem. But if it's just a regular quantum mechanics class, I would guess that you're supposed to assume the system is in its ground state.

It is a regular class.

diazona said:
By the way, be careful to actually figure out which energy levels are the lowest ones. Don't just assume that 001, 010, 100, etc. are in order of increasing energy.

Yep, I'm fully aware of that.

And I think n starts at 1 (111) since if one of them is 0, the wavefunction will also be equal to zero which is not true.

Thanks for the help!:smile:
 
  • #11
v_bachtiar said:
And I think n starts at 1 (111) since if one of them is 0, the wavefunction will also be equal to zero which is not true.
Oops, sorry :blushing: You're right, I wasn't paying attention.
 
  • #12
v_bachtiar said:
I do not know which permutations of n-values to choose though.

My guess is that the question is asking for the sum of the lowest 10 energies, so choose 10 permutations of n-values giving the lowest energies and sum them up. Then times this sum by 2 since each energy is occupied by 2 neutrons.

Would this be right?
Yes.

BTW, the prefactor on the energy expression in Post #1 corresponds to a temperature ~1012 K, so we can safely assume the system is in the lowest allowed state:
 
Last edited:

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