A billard ball of radius 'a' is intially spinning about a horizontal axis with angular speed w and with zero forward speed. If mu is the coefficent of sliding friction between the ball and the table, find the distance the ball travels before slipping ceases to occur.
Radius of gyration= 2/5*a^2, through the center of mass.
I*w=F(sub p)*r, where I is the moment of inertia, and F(sub p) is the fictional force parallel to the plane.
The Attempt at a Solution
So far, I have been able to determine that the intial velocity is equal to a*w(sub intial). But this doesn't do me much good.
I am more or less having a hard time trying to set up a force equation to solve.
I was thinking that the equation of motion would look something like this
m*a= (I*w)/a - f, where f (lower case) is the force due to friction).
But I don't think this is right.