- #1
Schaus
- 118
- 5
Homework Statement
The sixth term of the expansion of (x-1/5)n is -1287/(3125)x8. Determine n.
Homework Equations
tk+1=nCkan-kbk
The Attempt at a Solution
tk+1=nCkan-kbk
t5+1=nC5(x)n-5(-1/5)5
This is where I'm stuck. Do I sub in -1287/(3125)x8 to = t6? If so what do I do from here?
-1287/(3125)x8 = nC5(x)n-5(-1/5)5?
Any help is greatly appreciated!