Biology/Chemistry: pH Level and Ionizable Groups

[Soaring Crane]

Homework Statement

Select any molecule [from the assigned chapter] that has more than 2 ionizable groups. Write its structures, showing every atom, at pH levels 1 and 7.

Homework Equations

See below.

The Attempt at a Solution

http://en.wikipedia.org/wiki/Geranyl_pyrophosphate

The molecule that I chose is geranyl pyrophosphate:


____________________________________O_____O
____________________________________||____||
CH3C(CH3)=CHCH2CH2C(CH3)=CHCH2--O—P--O--P--O-
____________________________________|_____|
____________________________________O-____O-

This one does have 3 ionizable groups, right?

At pH 1, the molecule is under acidic conditions, so will all the ionizable groups be protonated?

____________________________________O_____O
____________________________________||____||
CH3C(CH3)=CHCH2CH2C(CH3)=CHCH2--O--P--O--P--OH
____________________________________|_____|
____________________________________OH____OH


At pH = 7, the presence of water can be presumed(?), so does this arise?


____________________________________O
____________________________________||
CH3C(CH3)=CHCH2CH2C(CH3)=CHCH2--O—P--OH
____________________________________|
____________________________________O-

+ __O
____||
HO--P--O-
____|
____O-


Thanks.

 

[Soaring Crane]

Revision here.

At pH 1, will all the groups be protonated like so?

____________________________________O_____O
____________________________________||____||
CH3C(CH3)=CHCH2CH2C(CH3)=CHCH2--O--P--O--P--OH
____________________________________|_____|
____________________________________OH____OH


At pH 7, will all the groups be unprotonated like so?

____________________________________O_____O
____________________________________||____||
CH3C(CH3)=CHCH2CH2C(CH3)=CHCH2--O—P--O--P--O-
____________________________________|_____|
____________________________________O-____O-

Or must I treat this like a triprotic acid in which each group is protonated at various instances? (If so, how do I go about doing this?)

Thank you.