Did I Make a Calculation Error in the Elastic Collision of Two Football Players?

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SUMMARY

The discussion centers on calculating the final velocity of Player 2 in an elastic collision between two football players, where Player 1 has a mass of 75 kg and a velocity of 6 m/s, and Player 2 has a mass of 150 kg and a velocity of -3 m/s. The correct formula for the final velocity of Player 2 is provided as Vfb = [(2*ma)/(ma+mb)]*Via + [(mb-ma)/(ma+mb)]*Vib. The user initially calculated Vfb as 3 m/s, while the online solution states it is -3 m/s, indicating a misunderstanding of the momentum principles involved in elastic collisions.

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Homework Statement


A collision occurs between two football players. Player 1 has mass of 75 kg and a velocity of 6 m/s. Player 2 has mass of 150 kg and a velocity of -3 m/s (meaning going in an opposite direction). Assuming an ELASTIC collision, what is the final velocity of player 2?

Homework Equations


They gave us this equation in class to calculate the final velocity:
m = mass
Vi = initial velocity
Vf = final velocity
a = player 1
b = player 2

Vfb = [(2*ma)/(ma+mb)]*Via + [(mb-ma)/(ma+mb)]*Vib

The Attempt at a Solution



Using the equation above and plugging in the numbers:

Vfb =
[(2*75kg)/(75kg + 150kg)]*(6 m/s)
+
[(150kg - 75kg)/(75kg + 150kg)]*(-3 m/s)

which gives me:

Vfb = 4 m/s + -1 m/s = 3 m/s


The "online" homework solution says it is -3 m/s. Am I incorrect? Did I miss a negative sign somewhere, or is there a principle of momentum that I am not getting?
 
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