Bismuth Telluride Bandstructure

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In summary, the conversation is about calculating the band structure of bismuth telluride using virtual nanolab and obtaining the band gap. The user asks about the F and U zones of brillouin and how to visualize the band gap. They also provide a CIF file for bismuth telluride and mention the polymorphism of the compound under high pressures and temperatures. The expert also gives some pointers on etiquette and asks the user about their knowledge on the subject.
  • #1
luigi9213
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Hello everyone

I need to calculate with virtual nanolab the bandstructure of bismuth telluride. I want to obtein the follow resoult or obtain the bandstructure to calculate the band gap.


The Band structure of Bi2Te3 is:
Bi2Te3.png


In virtual nanolab, with Hexagonal (and other) symmetry there aren't the F and U zone of brillouin...
Are they called in another way?

If nobody know virtual nanolab can say me how to obtain the bandstructure to visualize the bandgap?? Which brillouin zone i must plot? Has got the bismuthtelluride an hexagonal simmetry?


Here the .cif file of Bismuth telluride:

data_global
_chemical_name_mineral 'Tellurobismuthite'
loop_
_publ_author_name
'Atabaeva E Y'
'Ickevich E S'
'Mashkov S A'
'Popova S V'
'Vereshchagin L F'
_journal_name_full 'Fizika Tverdogo Tela'
_journal_volume 10
_journal_year 1968
_journal_page_first 62
_journal_page_last 65
_publ_section_title
;
The polymorphism of bismuth telluride under high pressures and temperatures
;
_database_code_amcsd 0012645
_chemical_formula_sum 'Bi2 Te3'
_cell_length_a 4.417
_cell_length_b 4.417
_cell_length_c 29.84
_cell_angle_alpha 90
_cell_angle_beta 90
_cell_angle_gamma 120
_cell_volume 504.178
_exptl_crystal_density_diffrn 7.912
_symmetry_space_group_name_H-M 'R 3 m'
loop_
_space_group_symop_operation_xyz
'x,y,z'
'2/3+x,1/3+y,1/3+z'
'1/3+x,2/3+y,2/3+z'
'x,x-y,z'
'2/3+x,1/3+x-y,1/3+z'
'1/3+x,2/3+x-y,2/3+z'
'-y,-x,z'
'2/3-y,1/3-x,1/3+z'
'1/3-y,2/3-x,2/3+z'
'-x+y,y,z'
'2/3-x+y,1/3+y,1/3+z'
'1/3-x+y,2/3+y,2/3+z'
'-y,x-y,z'
'2/3-y,1/3+x-y,1/3+z'
'1/3-y,2/3+x-y,2/3+z'
'-x+y,-x,z'
'2/3-x+y,1/3-x,1/3+z'
'1/3-x+y,2/3-x,2/3+z'
loop_
_atom_site_label
_atom_site_fract_x
_atom_site_fract_y
_atom_site_fract_z
Bi1 0.00000 0.00000 0.18800
Bi2 0.00000 0.00000 0.59800
Te1 0.00000 0.00000 0.38900
Te2 0.00000 0.00000 0.80000
Te3 0.00000 0.00000 0.00000
 
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  • #2
A few "etiquette" issues with your post:

1. Do not do multiple posts (read the PF rules).

2. When you are using data, results, or codes from other sources, you must provide adequate references references to them. This not only helps us to double check the sources, but it is also an ETHICAL thing to do. Otherwise, you are just "copying" stuff without giving credit to where you got this from. You need to learn how to do that anyway as you progress in your education, so might as well learn it now.

3. What exactly do you know? In this case, it appears that you simply copied someone's code. Do you even know the coordination number for this Bi-Te compound? What technique are you using to calculate this band structure? DFT? You gave no indication if you know how to do these things.

Zz.
 

1. What is the bandstructure of Bismuth Telluride?

The bandstructure of Bismuth Telluride is a graph that shows the relationship between the energy levels of electrons and the momentum of the crystal lattice. It is a crucial factor in understanding the electronic and thermal properties of this material.

2. How does the bandstructure of Bismuth Telluride affect its thermoelectric properties?

The bandstructure of Bismuth Telluride is responsible for its high thermoelectric performance. Its unique band structure allows for the efficient conversion of heat into electricity and vice versa, making it a valuable material for thermoelectric devices.

3. What is the significance of the bandgap in Bismuth Telluride's bandstructure?

The bandgap in Bismuth Telluride's bandstructure is crucial for its thermoelectric properties. This narrow gap between the valence and conduction bands allows for high electrical conductivity while maintaining low thermal conductivity, resulting in high thermoelectric efficiency.

4. How does the bandstructure of Bismuth Telluride change with temperature?

The bandstructure of Bismuth Telluride is highly temperature-dependent. As the temperature increases, the bandgap decreases, leading to a decrease in thermoelectric efficiency. This is due to the increase in electron-phonon scattering, which disrupts the material's electronic properties.

5. How is the bandstructure of Bismuth Telluride experimentally determined?

The bandstructure of Bismuth Telluride can be experimentally determined through various techniques such as angle-resolved photoemission spectroscopy, scanning tunneling microscopy, and X-ray diffraction. These methods allow scientists to analyze the energy levels and momentum of Bismuth Telluride's electrons and determine its bandstructure.

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