Black body radiation -- Spherical shell surrounding a star

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SUMMARY

The discussion centers on the misunderstanding of black body radiation as it relates to a spherical shell surrounding a star. The official solution, represented by the equations F=σ*T^4 and E=F*4πR^2*60*60, incorrectly implies that the energy radiated depends on the radius of the shell. Participants clarify that a body emitting 100 Joules per second will consistently radiate that amount regardless of the shell's size. The conversation highlights the importance of recognizing that the shell acts as a Gaussian surface, which does not radiate energy itself, and emphasizes the need for clarity regarding equilibrium conditions in the problem statement.

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Eitan Levy
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Homework Statement
A spherical shell with a radius of R surrounds a star with temperature T.

Find the amount of energy that the shell from the star in an hour.
Relevant Equations
[tex] P=\sigma*A*T^4 [/tex]
I don't understand how this can be solved.

The official solution was:

F=\sigma*T^4

E=F*4\pi R^2*60*60

This doesn't make sense to me, as it seems to imply that the energy that the black body radiates depends on the radius of the shell. For a very large shell the body will reflect "infinity" energy.

Can someone please explain this?

Thank you.
 
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If a body emits a total of 100 Joules per second and you enclose it completely with a shell, 100 Joules per second will pass through the entire shell no matter how large the shell is.
 
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kuruman said:
If a body emits a total of 100 Joules per second and you enclose it completely with a shell, 100 Joules per second will pass through the entire shell no matter how large the shell is.

That's what I figured! Is the solution wrong?
 
You should previously know the star's radius.
 
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Gordianus said:
You should previously know the star's radius.
The radius R of the surrounding shell is given. That ought to be enough.
 
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But at equilibrium the temperature of the shell is not the temperature of the star. That is the point and the OP is correct.
 
hutchphd said:
But at equilibrium the temperature of the shell is not the temperature of the star. That is the point and the OP is correct.
True, but there is no mention of equilibrium in the statement of the problem. My interpretation is that the shell is something like a Gaussian surface and not a material object.
 
Gaussian surfaces do not radiate. The ##\sigma T^4## is for the surface that radiates and is emitted power per area. You are making the same mistake as the Prof I fear.
 
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Perhaps the homework has a wording problem. I think the sphere of radius R is a sort of Gaussian surface that encloses the star (that radiates to the 2.7 K background). Thus, we should know the star's radius (call it a)
 
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You need to know the the temperature of some physical object of known radius. The problem as stated is not correctly solved.
No hand waving required. As pointed out astutely by the OP this leads to infinite power Dyson spheres.
 
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hutchphd said:
Gaussian surfaces do not radiate. The ##\sigma T^4## is for the surface that radiates and is emitted power per area. You are making the same mistake as the Prof I fear.
You fear correctly. Goes to show that I shouldn't be trying to do problems in my head.
 
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