CONFIG.SYS is the primary configuration file for the DOS and OS/2 operating systems. It is a special ASCII text file that contains user-accessible setup or configuration directives evaluated by the operating system's DOS BIOS (typically residing in IBMBIO.COM or IO.SYS) during boot. CONFIG.SYS was introduced with DOS 2.0.
Doing some revision and getting confused. It's under GR but may as well be under electromagnetism or calculus because that is where the problem is. Taking a shell of mass ##\rho = M\delta(r-R)/(4\pi R^2)## and four velocity corresponding to rotation about ##z## axis i.e. ##U = (1, -\omega y...
https://linux-training.be/funhtml/ch18.html
echo hello > greetings.txt
I feel it's telling before counting the number of arguments, redirection operator is ignored.
But later it says how it affects output erasing file case.
[paul@RHELv4u3 ~]$ cat winter.txt
It is cold today!
[paul@RHELv4u3...
I will copy paste a post i made on another forum.Its just a fun project i started and i hope people in here are going to be able to help.I am not an aerospace engineer but im studying electrical and electronic engineering so i am familiar with formulas math and physics (up to a degree of...
Here is figure 2.16.6
Here is the picture I drew to set up the problem
My first question is if the reasoning and integrals are correct. I used Maple to compute the three integrals. The first two result in 0, which makes sense by symmetry.
Maple can't seem to solve the last integral.
If we call a nucleus a sd shell nucleus, should its last proton and last neutron both lie in the sd shell or just one lies in the sd shell?
For example, 15F, whose proton number is 9 and neutron number is 6. Then the last proton lies in the 1d5/2 orbit and the last neutron lies in the 1p3/2...
Hello all!
I have a earring project with magnets involved but no magnet expert involved :( Here are a few stupid questions I hope someone can help us with!
BACKGROUND:
We are designing magnetic earrings. The earrings are meant to clamp the ear with 3 different levels of pressure. The magnetic...
What does and observer inside of a collapsing shell observe? Lets say we have a shell of matter collapsing to a black hole. What would observers near the center see? How would the rest of the universe appear when,
The shell is approaching the Schwarzschild radius?
After the shell passes the...
The electric field inside a charged spherical shell moving inertially is, per Gauss's law, zero.
If the spherical shell is accelerated, the field inside is not zero anymore, but it gains a non-null component along the direction of the acceleration, as mentioned, for example, in this paper.
The...
The independent particle energies for protons and neutrons around the
exotic doubly magic core 132Sn are shown in the figure below, where
π refers to protons and ν to neutrons.
Using the nuclear shell model and using this figure as a guide, answer
to the following questions:
a)Estimate Jπ...
Hi Everyone.
Can anyone give me some hints which will point out how to solve this problem, particularly using 'the formalism of Ex 21.25'.
I've kicked this around for a couple of weeks now and I haven't been able to come up with anything.
Regards
TerryW
Using the equation above, I plugged in 5.5 inches for the radiu and 0.5 inches for the value of dr and then solved for the estimate of the change in volume, dV. However, the solution instead uses a value of 6 inches for the radius receiving a different estimate for the problem than I did. Is my...
In general relativity, rotation of mass gives rise to framedraging effects, just like linear motion does, because of the off-diagonal components in the mass-energy-momentum tensor. So around Bonnor beams there is framedragging, as well around a rotating mass.
Now imagine a spherical rotating...
I worked this problem out in griffiths and my work checks out for for the potentials, b.c. and the coefficients. I will post the solutions just because my work is a little harder to read.
What I am having trouble finding is the dipole moment of the conductor.
I know the formula for dipole...
First draw a gaussian shape outside of the sphere (a larger sphere) with radius R. The total charge from the (inner) sphere will be:
$$Q = \sigma A$$
$$A = 4\pi r^2$$
$$Q = \sigma 4\pi r^2$$
Use Gauss's Law to derive electric field magnitude
$$\oint_{}^{} E \cdot dA = \frac{q_e}{\epsilon_o}$$...
Ubuntu has given me a far more stable working system compared to Windows and its buggy updates. But, once in a while, I do find GNOME becoming slow or even crashing. If I find that the GUI is becoming unresponsive, I promptly restart GNOME using Alt + F2 → r → Enter This does the job most of the...
Hi all,
I am currently trying to prove formula 21 from the attached paper.
My work is as follows:
If anyone can point out where I went wrong I would greatly appreciate it! Thanks.
Black holes form. An undeniable fact. Let's imagine a massive shell collapsing under its own weight (the exact composition of the mass is not important, so just imagine to be a continuous mass with zero thickness).
What happens if the process of collapse evolves? The time on the inside will run...
A known result is that the average field inside a sphere due to all the charges inside the sphere itself is proportional to the dipole momentum of the charge distribution (see, for example, here).
I wonder whether the same result can be applied in the case of a spherical shell of non-uniform...
My approach is thus: the shell will have induced charges if it's conducting resulting in E at the centre of shell(though flux at centre will be 0). For non conducting spheres there can be no induction only polarization of dipoles, therefore the E field at centre will remain 0. Is my approach...
let's consider spherically symmetrical thin shell of dust, which is collapsing under its own gravity. There are no other forces as pressure or so except gravity, and particles of shell (dust) are in free fall. The shell has total mass M and collapse starts from rest state with diameter of the...
delta q=rho deltaV
rho=dq/dV
dq=rho4pir^2dr
Then integrate dq from 0 to a because A is to be uniform in shell.
Ans: A= 5.3*10^-11 C/m^2
How do we approach these problems? Looking at the answer A seems to be surface charge density. What is A? What is the direction of uniform field E. I don’t...
When I look at the relevant equations, then there is no mention of field for a point on the surface of the shell, so it gets confusing. On the other hand, I feel the radial E will get stronger as we approach the surface of shell and magnitude of E will approach infinity.
The only explanation that I have seen in textbooks is that since the outer spherical shell is symmetrical relative to internal charged spherical shell so field every where on the outer shell is same in magnitude at every point on it.
I can understand that electric field needs to be...
So let's say we have a large neutral atom, e.g. gold with 79 electrons around it. Let's say we replace its outermost electron with a muon. Muons orbit closer to the nucleus than electrons, much closer. Will the outermost muon be closer into the nucleus than even its innermost ground-state...
So here was my first go around at it:
At first it made sense in my head but don't think my process is correct. Then i noticed the example in the book:
I guess the reasoning isn't 100% there in my head and if i don't have an actual σ, how will i cancel out any legendre polynomials due to...
I don't understand how this can be solved.
The official solution was:
F=\sigma*T^4
E=F*4\pi R^2*60*60
This doesn't make sense to me, as it seems to imply that the energy that the black body radiates depends on the radius of the shell. For a very large shell the body will reflect...
I was able to solve this problem easily by using the fact that the center of mass of the system is stationary as ##\sum F_{ext} = 0## for the ball and shell system. since COM's of both objects can be replaced with point masses at there center, the shell will have maximum displacement when its...
According to my professor, the solution in this book (pages 20-21) for item (ii) is wrong: https://www.u-cursos.cl/usuario/75468645ed16a71af6da3ffd813d47f5/mi_blog/r/Problems_and_Solutions_on_Electromagnetism.pdf
First, the correct answer is μ0*π*R^2.
I tried to look at the cylinder like it was a solenoid, this technique was used in my class.
Then I tried to find the current of the solenoid, to do that I looked at a piece of a solenoid with a legnth of dz, then:
I=dq/dt=(2πRσ*dz)/(2π/ω)=ω*R*σ*dz.
The...
So for the Gaussian theorem we know that $$ \frac{Q}{e} = \vec E \cdot \vec S $$ Q's value is known so we don't need to express it as $$Q=(4/3)\pi*(R_2 ^3-R_1 ^3)*d$$ where d is the density of the charge in the volume. I've expressed the surface $$S=4\pi*x^2$$ where x is the distance of a point...
I've been discussing Newton's Shell Theorem re: gravity with someone, and thought of the analogy to charge.
1. I think the net effect on a negative charge inside a hollow sphere of positive charge will be zero. i.e. No net attraction. Yes?
2. But what would happen to the magnetic field if the...
First i tried proving Newton shell theorem directly for r=R and solved the integral as above but still got the wrong solution.
Here i tried using general case:
Here r' is the distance of a small ring from the point particle of mass m
So my doubt is when we take r=R and then evaluate this...
Homework statement:
Find the electric field a distance z from the center of a spherical shell of radius R that carries a uniform charge density σ.
Relevant Equations: Gauss' Law
$$\vec{E}=k\int\frac{\sigma}{r^2}\hat{r}da$$
My Attempt:
By using the spherical symmetry, it is fairly obvious...
a. This solution is i can consider the charge Q as a point charge and the electric potential at a distance r is
## V = Q/(4πεοr)##
b. This is where the confusion starts again when r2>r>r1, my answer
##
V = ρ*4*π(r^3 - r_1^3)/(3*4πεοr) \\
V = ρ*(r^3-r_1^3)/3εοr; ##
I know i am making some...
Dear FEA experts,
I’m trying to analyse* some finite elements model of a thin walled cylinder with variable cross-section, but I’m observing four weird issues in the buckling modes. The structure is vertically (along z-axis) and horizontally (along y-axis) loaded on top. Would you help me to...
Homework Statement: Derive the formula for the moment of inertia of a thin spherical shell using spherical coordinates and multiple integrals.
Homework Equations: Moment of Intertia is (2MR^2)/3
I = (2MR^2)/3
Hi, been a while since I last asked here something.
I am restudying electrostatics right now, and I am facing difficulties in the following question:
My attempt:
I tried to use Gauss' law, what I got is the equation in the capture but that doesn't lead me anywhere as I am unable to find a...
Hello. I have figured out a few things about ST-type exchangers and I intend to build a reactor with this new knowledge. I have a rather... small problem.
So I searched for shell diameter correlations given the pitch and number of tubes and I found this from a writeup:
Apparently, it's from...
I watched Ghost in the Shell 1995 the other night. It was cartoon. At first I was hesitant being just cartoon. But found it so intriguing, then I rewatched again the 2017 live version staring Johansson Scarlett.
I noticed the 1995 cartoon version was more well-received (Tomato score 96%) than...
Hi! I need help with this problem. I tried to solve it by saying that it would be the same as the field of a the spherical shell alone plus the field of a point charge -q at A or B. For the field of the spherical shell I got ##E_1=\frac{q}{a\pi\epsilon_0 R^2}=\frac{\sigma}{\epsilon_0}## and for...
The textbook says
' A conducting sphere shell with radius R is charged until the magnitude of the electric field just outside its surface is E. Then the surface charge density is σ = ϵ0 * E. '
The textbook does show why. Can anybody explain for me?
Hi! I need help with this problem. I tried to do it the way you can see in the picture. I then has this:
##dE_z=dE\cdot \cos\theta## thus ##dE_z=\frac{\sigma dA}{4\pi\epsilon_0}\cos\theta=\frac{\sigma 2\pi L^2\sin\theta d\theta}{4\pi\epsilon_0 L^2}\cos\theta##.
Then I integrated and ended up...