Black holes, white dwarfs and neutron star - Shapiro, Teukolsky

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SUMMARY

The discussion focuses on Exercise 2.6 from a physics homework assignment, which involves calculating the electron fraction per baryon in a mixture of hydrogen and helium. The key formula derived is μ_e = m_B / (m_u Y_e), where m_B represents the baryon rest mass and Y_e is the number of electrons per baryon. Participants clarify the definitions of mass fractions X and Y, leading to the conclusion that X = n_H / (n_H + n_He A_He) and Y = n_He / (n_H + n_He A_He). The discussion emphasizes the importance of weighted averages in mixtures of different atomic species.

PREREQUISITES
  • Understanding of baryon rest mass and its calculation
  • Familiarity with atomic mass units and the concept of mass fractions
  • Knowledge of the relationship between atomic species and their contributions to electron count
  • Basic grasp of weighted averages in mixtures of elements
NEXT STEPS
  • Study the concept of baryon number and its implications in astrophysics
  • Learn about the role of electron fractions in stellar evolution
  • Explore the calculations involved in nuclear reactions in stars
  • Investigate the properties of neutron stars and their composition
USEFUL FOR

Students and researchers in astrophysics, particularly those focusing on stellar composition and nuclear physics, will benefit from this discussion.

Vrbic
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Homework Statement


Exercise 2.6 (page 28)
Consider completely ionized matter consisting of hydrogen, helium, and heavier atomic species i>2. Let X and Y denote the fractions by mass of hydrogen and helium, respectively. Show that
\mu_e=\frac{2}{1+X}.
Approximate m_i=A_i m_u for all i, and take Z_i/A_i=1/2 for i>1.

Homework Equations


\mu_e=\frac{m_B}{m_uY_e} \\<br /> m_B=\frac{\sum{n_i m_i}}{\sum{n_i A_i}} baryon rest mass, where m_u is mass of nucleon, Y_e=Z/A is number of electrons per baryon.

The Attempt at a Solution


I didn't find definition of X and Y but I suppose X=m_H/m_{tot} =. I am quit confused so I can't realize how proceed.
 
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Vrbic said:
I didn't find definition of X and Y
It is defined in the problem statement, and you found the right formula.
$$\mu_e=\frac{m_B}{m_uY_e}$$
This is for a single element. For the total mixture, you'll need a weighted average.

Here is an easier version of the problem: if you have 200 hydrogen nuclei and 100 helium nuclei, how many electrons per baryon do you have, and what is the mass fraction of hydrogen?
What about 100 and 100 nuclei? Or arbitrary numbers?
 
mfb said:
Or arbitrary numbers?
For Hydrogen: M_H=n_H m_u, for Helium: M_{He}=n_{He}A_{He}m_{He} Than
X=\frac{n_H m_u}{n_H m_u+n_{He}A_{He}m_{u}}=\frac{n_H}{n_H+n_{He}A_{He}} and Y=\frac{n_{He} m_u}{n_H m_u+n_{He}A_{He}m_{u}}=\frac{n_{He}}{n_H+n_{He}A_{He}}.
So than I mean amount eletroncs per baryon is Y_e=\frac{n_{H}+Z_{He}n_{He}}{n_H +n_{He}A_{He}}=\frac{n_{H}+n_{He}A_{He}/2}{n_H+n_{He}A_{He}}. Ok?
 

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