Boolean Algebra Problem: Solution for AB vs. A(comp(B)+c)

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Discussion Overview

The discussion revolves around a Boolean algebra problem concerning the simplification of the expression AB versus A(comp(B)+c). Participants are examining the validity of the model answer provided in a textbook against their own simplifications.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant claims to have simplified the expression to AB, questioning the correctness of the model answer A(comp(B)+c).
  • Another participant suggests checking the output for specific values, indicating that the output for A and B should be evaluated with different values for C.
  • A third participant notes that the model answer produces a 1 output for certain inputs, which contradicts their simplification that yields a 0 output when B=0.
  • A later reply proposes that to achieve the textbook's answer, a missing inverter must be restored to ensure the correct input is fed into the AND gate.

Areas of Agreement / Disagreement

Participants express disagreement regarding the validity of the model answer versus their own simplifications. No consensus is reached on which expression is correct.

Contextual Notes

There is a suggestion that a missing inverter may be a critical factor in determining the correct output, indicating potential limitations in the initial problem setup.

waver.
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members are warned that removing diagrams from homework threads is against PF rules
https://scontent-mxp1-1.xx.fbcdn.net/v/t35.0-12/13324008_10209600482268675_3779883_o.png?oh=abd4c815b9472f70cfbfbb1923a37b3c&oe=5752F454

Number 12 : I have simplified it and I have got AB but the model answer in red say A(comp(B)+c)
I just want is that answer true or not , thanks in advance
 
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Why don't you check yourself? What is the output if ##A \overline B## (and choose whatever you like for C)?
 
You are right. You can easily see that every input that includes B=0 gives a 0 output, when by the answer in red (A,B,C)=(1,0,0) for example should give 1.
 
To get the textbook's answer, you need to restore a missing inverter so the upper AND gate receives ##\overline B## at its lower input.
 
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