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Skatch

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Can someone tell me if the following statement is true?

Say you have [tex]P(x)e^{Q(x)}[/tex] where P(x) is any finite-degree polynomial and Q(x) is a polynomial of integer order k. Is it true that for any positive epsilon, I can find some real numbers A and B such that

[tex]|P(x)e^{Q(x)}| \leq Ae^{B|x|^{k+\epsilon}}\quad \forall x ?[/tex]

I don't need a proof, just some intuition about why its true or a counterexample if its not. I figure since the expression on the right will be growing faster than that on the left, I should be able to find some A and B to ensure the RHS will always be larger, right? Is this an obvious statement or am I crazy??

Edit: I think its true since the smallest the right hand side can be is A at x=0. So I choose A so that the RHS is larger at x=0, and B is chosen to ensure that its larger around zero, and then far from zero the growth of the exponent on the RHS will dominate and we are home free... This is the idea, yes?

Say you have [tex]P(x)e^{Q(x)}[/tex] where P(x) is any finite-degree polynomial and Q(x) is a polynomial of integer order k. Is it true that for any positive epsilon, I can find some real numbers A and B such that

[tex]|P(x)e^{Q(x)}| \leq Ae^{B|x|^{k+\epsilon}}\quad \forall x ?[/tex]

I don't need a proof, just some intuition about why its true or a counterexample if its not. I figure since the expression on the right will be growing faster than that on the left, I should be able to find some A and B to ensure the RHS will always be larger, right? Is this an obvious statement or am I crazy??

Edit: I think its true since the smallest the right hand side can be is A at x=0. So I choose A so that the RHS is larger at x=0, and B is chosen to ensure that its larger around zero, and then far from zero the growth of the exponent on the RHS will dominate and we are home free... This is the idea, yes?

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