Work. That is an amount of energy, isn't it? Hmmm... One of your relevant equations involves energy. But the others do not. Maybe figure out some more equations involving energy.IAmBadAtMath said:Homework Statement:: A bowling ball is pushed down a steep hill with a mass of 8.2kg. Its initial velocity is 3,0 m/s. When the ball arrives at the bottom of the hill its velocity is 26.5 m/s. How much work has the resistance forces done to slow the bowling ball down.
Relevant Equations:: v = v_0 + at, an = v2/r, W = Fs, g = 9,81 m/s^2,
I have no idea how and what to do.
It's all there. None of the entered formulas are relevant, though.jbriggs444 said:I do not see all of the information that I would expect. Are you sure you've quoted the whole thing?
Show some work : forum rules. Maybe explain what you think the problem is, without simply cut'n'pasting.IAmBadAtMath said:I have no idea how and what to do.
There's a nice juicy hint right there, for when you get around to figuring out how to solve it.jbriggs444 said:Work. That is an amount of energy, isn't it?
Possibly a browser problem. I do not see the attached diagram, except as something ephemeral that I managed to mouse over one time. The text does not reveal the height of the hill.hmmm27 said:It's all there. None of the entered formulas are relevant, though.
Nope. Irrelevant.hmmm27 said:Okay, now you got me wondering if the magnitude of the circumference is necessary.
I would agree with this interpretation. Probably the ball slides a distance of many circumferences before undergoing one revolution about its axis. Nevertheless, we still need a vertical drop.jbriggs444 said:The adjective "steep" is the piece that leads me to the opposite interpretation. But no matter. If sliding friction is absent, air resistance can suffice and the problem is still identical either way as long as rolling is established at top and bottom.
I assumed any losses to be mainly as rolling resistance.hmmm27 said:The verb "rolled" in the title is my stance... despite the problem statement's lack of clarification. Picture a long, mildly sloped bowling lane on the beach.
The steeper the hill, the faster the bowling ball will roll. This is because the force of gravity pulling the ball down the hill increases with the steepness of the slope.
The main factors that affect the distance the bowling ball will travel down the hill are the initial velocity of the ball, the slope of the hill, and the presence of any external forces such as friction or wind resistance.
The weight of the bowling ball does not have a significant impact on its movement down the hill. As long as the ball is heavy enough to overcome any friction or resistance, it will roll down the hill at a similar speed regardless of its weight.
Yes, the shape of the bowling ball can affect its speed down the hill. A more aerodynamic shape will experience less air resistance and therefore roll faster down the hill.
Friction plays a crucial role in the bowling ball's movement down the hill. Without friction, the ball would continue to roll at a constant speed down the hill. However, friction between the ball and the surface of the hill will slow down its speed and eventually bring it to a stop.