What impulse must act on the bowling ball to stop it?

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SUMMARY

The discussion centers on calculating the impulse required to stop a 10kg bowling ball moving at -3m/s. The momentum of the bowling ball is determined to be -30 Ns using the formula momentum = mv. To bring the bowling ball to a stop, an impulse of 30 Ns must act on it, which is equal in magnitude but opposite in direction to the initial momentum. This confirms that impulse represents a change in momentum, and the necessary impulse is indeed equal to the initial momentum of the bowling ball.

PREREQUISITES
  • Understanding of momentum and impulse concepts
  • Familiarity with the equations momentum = mv and impulse = ΣFΔt
  • Basic knowledge of Newton's laws of motion
  • Ability to perform calculations involving mass and velocity
NEXT STEPS
  • Study the relationship between impulse and momentum in various contexts
  • Learn about the application of Newton's laws in real-world scenarios
  • Explore examples of impulse in sports physics, particularly in bowling
  • Investigate the effects of different forces acting on moving objects
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of momentum and impulse in action.

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Homework Statement


[/B]
A 10kg bowling ball is moving with a velocity of -3m/s.
a) What is the momentum of the bowling ball?
b) What impulse must act on the bowling ball to bring it to a stop?

Homework Equations



momentum=mv
impulse=ΣFΔt
ΣFΔt=mΔv

The Attempt at a Solution



a) momentum = mv
momentum = (10)(-3)
momentum = -30Ns

b) This is where I get stuck. Is the impulse simply equal and opposite to the momentum? Or is there another step?

ΣFΔt=mΔv
ΣFΔt=-30Ns
ΣFΔt=30Ns (opposite sign because bowling ball has to be stopped by a force going in the other direction)
 
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Impulse represents a change in momentum. The change you want in this case happens to be equal in magnitude to the initial momentum of the bowling ball. So you've done fine.
 

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