Bremstrahlung Radiation: Understanding the Three Vertex Feynman Diagram

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Discussion Overview

The discussion revolves around the Feynman diagram for Bremstrahlung radiation, specifically addressing the presence of three vertices in the diagram and the processes involved in electron interactions with photons and nuclei. The scope includes theoretical aspects of particle physics and conceptual clarifications regarding terminology.

Discussion Character

  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions why the Feynman diagram for Bremstrahlung radiation features three vertices, suggesting that an electron decays into a photon and a virtual electron, which then decays into another photon and a lower energy electron.
  • Another participant clarifies that while an electron can decay into another real electron and a photon, this process is referred to as Rutherford scattering, not Bremstrahlung.
  • A further contribution emphasizes the confusion around the term "decay," suggesting that "emission" or "radiation" is a more accurate description of the electron's interaction, as it remains present after the process.

Areas of Agreement / Disagreement

Participants express differing views on the terminology used to describe the processes involved in Bremstrahlung radiation, with some agreeing on the definitions while others highlight the potential for confusion. The discussion does not reach a consensus on the terminology but clarifies the distinction between Bremstrahlung and Rutherford scattering.

Contextual Notes

The discussion highlights limitations in the use of specific terms like "decay," which may lead to misunderstandings about the processes being described. There is also an implicit dependence on the definitions of scattering and radiation in particle physics.

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why is it that the feynman diagram illustrating Bremstrahlung radiation has three vertices; basically an electron decays into a)a photon which recoils the nucleus and b)a virtual electron WHICH THEN decays into another photon and an electron of lower energy.

why can't the original electron just decay into another REAL electron (plus the photon), like in Compton scattering?
 
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It can do that, but that's called Rutherford scattering, not bremsstrahlung.

By definition, bremsstrahlung involves 2 processes: an electron decelerates due to an external field, and it emits real radiation.
 
vertices said:
why is it that the feynman diagram illustrating Bremstrahlung radiation has three vertices; basically an electron decays into a)a photon which recoils the nucleus and b)a virtual electron WHICH THEN decays into another photon and an electron of lower energy.

why can't the original electron just decay into another REAL electron (plus the photon), like in Compton scattering?

Phlogistonian gave the answer. But let me add that it's confusing when you use the term "decay" here. Decay is used when a particle transforms into other particles. Here the electron does not "decay" since it's still there after. The way people would normally describe what happens is that the electron "emits" or "radiates" a photon. So the process you are describing is that an electron emits a photon absorbs by the nucleus and then a second, real photon. If no real photon is emitted than this is is just Rutherford scattering, not Bremsthrahlung, as Phlogistonian said.
 
thanks Phlogistonian and nrqed...

(and yes ofcourse I was misusing the word 'decay' in this context)
 

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