Why is the probability of one player holding all spades 1/(52C13)?

[davedave]

In the game of bridge, four players are dealt 13 cards each from a well-shuffled deck of 52 playing cards.

(a)What is the probability that one of the players is dealt all the spades?
(b)What is the probability that one of the players holds a hand that is made up of only one suit?

(a) There is only one way to choose all 13 spades.
52C13 ways to choose any 13 cards
So, 1/(52C13)

(b) Since there are 4 different suits, the probability is 4/(52C13).

Does anyone know why my answers are wrong? Thanks.

 

[tiny-tim]

hihi davedave!

In the game of bridge, four players are dealt 13 cards each from a well-shuffled deck of 52 playing cards.

(a)What is the probability that one of the players is dealt all the spades?
(b)What is the probability that one of the players holds a hand that is made up of only one suit?

i think they mean any one of the players (ie, not a particular player)