Bridge Card Game: Finding the Probability of Spades & One-Suit Hands

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SUMMARY

The discussion focuses on calculating probabilities in the game of bridge, specifically the likelihood of a player being dealt all spades and the probability of a player holding a hand made up of only one suit. The correct probability for a player receiving all spades is calculated as 1/(52C13), where 52C13 represents the combinations of choosing 13 cards from a deck of 52. For a player holding a hand of only one suit, the probability is 4/(52C13), accounting for the four suits available in the deck.

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davedave
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In the game of bridge, four players are dealt 13 cards each from a well-shuffled deck of 52 playing cards.

(a)What is the probability that one of the players is dealt all the spades?
(b)What is the probability that one of the players holds a hand that is made up of only one suit?

(a) There is only one way to choose all 13 spades.
52C13 ways to choose any 13 cards
So, 1/(52C13)

(b) Since there are 4 different suits, the probability is 4/(52C13).

Does anyone know why my answers are wrong? Thanks.
 
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hihi davedave! :smile:
davedave said:
In the game of bridge, four players are dealt 13 cards each from a well-shuffled deck of 52 playing cards.

(a)What is the probability that one of the players is dealt all the spades?
(b)What is the probability that one of the players holds a hand that is made up of only one suit?

i think they mean any one of the players (ie, not a particular player) :wink:
 

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