Brocard's Problem: No Solution for n! Containing Prime^2, n>7?

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Discussion Overview

The discussion centers on Brocard's problem, specifically investigating integer values of n for which n! + 1 = m^2, with a focus on the condition that n! contains a prime raised to the power of exactly 2 for n > 7. Participants are examining potential proofs and results related to this problem.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant claims to have a proof that there are no solutions for n! containing a prime with power exactly 2 when n > 7, and seeks feedback on this proof.
  • Another participant humorously questions why the proof has not been shared, suggesting possible technical difficulties.
  • A participant mentions using long integer arithmetic to find no additional solutions for n < 100, aside from n = 4, 5, and 7.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus, as there are competing views regarding the existence of solutions and the validity of the proposed proof.

Contextual Notes

Limitations include the lack of detailed presentation of the proof and the specific conditions under which the claims are made, particularly regarding the nature of prime powers in factorials.

secondprime
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Brocard's problem asks to find integer values of n for which
n! + 1 =m^2 .
where n! is the factorial.Probably I got a proof that there is no solution if n! contains a prime with power exactly 2 & n>7...looking for error...anyone else with any result?
 
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and you did not post your proof because you run out of ink? or maybe your computer crashed.
 
I have enough ink but don't know how to write with ink on computer:smile: trying to find an error in my proof,so asking about any result related to the problem.
 
Using long integer arithmetic, I found (besides n= 4, 5, 7) no other solutions for all n < 100
 

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