ceptimus
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alex caps said:Isn't the thrust equation [tex]$\pi$ r^2/t[/tex] ?
if that is right, where does the 4 come from?
The area of a circle is [tex]\pi r^2[/tex] but [tex]\pi d^2/4[/tex] works out exactly the same (where d is the diameter, twice the radius).
The thrust formula for a propeller, if you assume that a pressure difference, p acts evenly over the area of the disc the propeller sweeps out is:
[tex]t = p * \pi d^2/4[/tex]
We have been working in non-SI units of pounds (lb), inches and pounds per square inch (psi), so if we have a pressure difference of 1/50 psi and a propeller diameter of 5 inches, we get a thrust on the propeller disk of:
[tex]t = 0.02 * \pi * 5^2/4 \approx 0.393 lb[/tex]
Remember the lifting force on the hovercraft is much more than this, as the pressure difference acts over the whole area of the hovercraft, not just the fan disk.