Building a Telescope: Calculating Total Magnification & Length

AI Thread Summary
The total magnification for the telescope using a 2x objective lens and a 5x eyepiece is calculated to be 10x. The 2x lens is chosen as the objective due to its longer focal length and lower magnification. To determine the telescope's length, the focal lengths of the lenses are required, but these are not provided in the problem statement. A formula relating magnification to focal length is mentioned, but it is not necessary for calculating telescope specifications. The discussion emphasizes the importance of knowing the focal lengths to accurately compute the telescope's length.
frostking
Messages
21
Reaction score
0

Homework Statement


I need to build a telescope from two magnifying lens, one is 2x the other is 5x. First I need to give the total magnification possible, state which lens to use as the objective and finally to state the length of the telescope.


Homework Equations


l Ml = Fo/Fe total magnification is lM1l x lM2l Length = Focal length of objective + focal length of eyepiece


The Attempt at a Solution

The total possible magnification is 10X. I use the 2X for the objective because you need a long focal length and smaller magnification. I am stuck on how to get the length of the scope. I know the absolute value of M and can say that Fobjective is equal to lMl times F of eyepiece. But I don't have either focal length as far as I can tell and so I have no way to determine the length. I have the answer, so I know it should be 55 cm but why? Any help would be much appreciated. Frostking
 
Physics news on Phys.org
There's a formula that relates the magnification of a magnifying glass with its focal length. Do you know what it is?
 
Yes, silly me it is M = 25/F On exams we are only allowed to use formulas on our formula sheet or that can be derived from the formula sheet. This formula is NOT provided. I guess I will just have to memorize this and hope that it is allowed to be used on the final. Thanks and sorry for wasting your time. Frostking
 
This formula is valid for magnifying glass. You don't need it for telescope.
For a telescope the magnification is given by the ratio of the two focal lengths.
 
nasu said:
This formula is valid for magnifying glass. You don't need it for telescope.
For a telescope the magnification is given by the ratio of the two focal lengths.

Thanks so much. I will remember this and use it! Frostking
 
You don't need the formula for a telescope, but the specifications of the magnifying glasses are given. I can't see how you would find the ratio of the focal lengths without using these specifications.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top