V^2=Ae^-2kx - g/k (upward motion)(adsbygoogle = window.adsbygoogle || []).push({});

V^2=g/k - Be^2kx (downward motion)

Use the above result to show that , when the bullet hits the ground on its return, the speed will be equal to the expression

Vo Vt / (Vo^2 + Vt^2)^0.5

In which Vo is the initial upward speed and Vt= (mg/C2)^0.5= terminal speed = (g/k)^0.5

This is result allows one to find the fraction of the initial kinetic energy lost through air friction

THIS PROBLEM WILL KILL ME I SPEND DAYS TO SOLVE IT BUT I COULD NOT:(

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# Homework Help: Bullet hits the ground on its return

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