SAHM1500
- 5
- 0
V^2=Ae^-2kx - g/k (upward motion)
V^2=g/k - Be^2kx (downward motion)
Use the above result to show that , when the bullet hits the ground on its return, the speed will be equal to the expression
Vo Vt / (Vo^2 + Vt^2)^0.5
In which Vo is the initial upward speed and Vt= (mg/C2)^0.5= terminal speed = (g/k)^0.5
This is result allows one to find the fraction of the initial kinetic energy lost through air friction
THIS PROBLEM WILL KILL ME I SPEND DAYS TO SOLVE IT BUT I COULD NOT:(
V^2=g/k - Be^2kx (downward motion)
Use the above result to show that , when the bullet hits the ground on its return, the speed will be equal to the expression
Vo Vt / (Vo^2 + Vt^2)^0.5
In which Vo is the initial upward speed and Vt= (mg/C2)^0.5= terminal speed = (g/k)^0.5
This is result allows one to find the fraction of the initial kinetic energy lost through air friction
THIS PROBLEM WILL KILL ME I SPEND DAYS TO SOLVE IT BUT I COULD NOT:(
