- #1

needhelp83

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E=(1/2)kA^2=(1/2)(2250 N/m)(0.124 m)2=17.30 J

m=0.0125 kg + 0.3 kg=0.3125 kg

K=(1/2)mv^2

17.30 J=(1/2)(0.3125 kg)v^2

v2=0.009

v=0.095 m/s

Conservation of momentum:

(.0125 kg)v=(0.3125 kg)(0.095 m/s)

v=2.375 m/s

Have I done this properly? The velocity doesn't seem right to me. Have I missed anything?