- #1

naji0044

- 7

- 0

Hey everyone

I'm struggling on the last part of this assignment. I need to find the total work done by the block and the bullet, when the collision happens. The informations is:

mblock=0.3 kg

mbullet=0.01 kg

vg=700 m/s

Height=0.72m

The final speed after the collision is vf=22.6 m/s and the distance X=8.66 which i have calculated.

My thought on the work done on the bullet must be kinetic energy that is impressed as K=1/2*m*vg^2

The work done on the block is probably using (k-k0)+(U-U0)=0, where we have potentiel energy. Picture of the situation is showed in the picture down below. Would appreciate if you could tell me which kind of formula you are using and why

I'm struggling on the last part of this assignment. I need to find the total work done by the block and the bullet, when the collision happens. The informations is:

mblock=0.3 kg

mbullet=0.01 kg

vg=700 m/s

Height=0.72m

The final speed after the collision is vf=22.6 m/s and the distance X=8.66 which i have calculated.

My thought on the work done on the bullet must be kinetic energy that is impressed as K=1/2*m*vg^2

The work done on the block is probably using (k-k0)+(U-U0)=0, where we have potentiel energy. Picture of the situation is showed in the picture down below. Would appreciate if you could tell me which kind of formula you are using and why

**[Moderator's note: Moved from a technical forum and thus no template.]**
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