Bullet passing through two holes

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    Bullet Holes
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SUMMARY

The problem involves calculating the speed of a bullet passing through two rotating paper disks positioned 0.082 meters apart. The angular displacement of the bullet holes is 24.9 degrees, and the disks rotate at a speed of 819 revolutions per minute. To find the bullet's speed in meters per second, one must convert the rotational speed to radians per second, determine the time taken for the bullet to travel between the holes using the angular displacement, and then apply the formula for speed using the distance between the disks.

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  • Understanding of angular displacement and its units
  • Knowledge of rotational speed conversion (revolutions per minute to radians per second)
  • Familiarity with kinematic equations, specifically speed calculations
  • Basic grasp of circular motion concepts
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Homework Statement


so this is a classic problem...if you know what i mean.

The speed of a moving bullet can be determined by allowing the bullet to pass through two rotating paper disks mounted a distance .082m apart on the sam axle. from the angular displacement 24.9 degree of the two bullet holes in the disks and the rotational speed 819rev/min of the disks.
What is the speed of the bullet. in m/s^2


Homework Equations





The Attempt at a Solution


I try to find time from the starting point of the bullet till the second hole

time=(distance*2pi)/(full revolution of the disk*the degree)
then use that time and put it in the equation of
x final= velocity initial*time.

but didnt get it so any suggestion?
 
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First you should change the rotational speed into usefull units ie radians or degrees per second

Second, you need to use the angular displacement and the rotational speed to find the time it took for the bullet to pass from first to second piece of paper.

Third you will need to use this time and then the distance between the bits of paper to calculate the speed of the bullet. Done!
 

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