Buoyant Force acting on a sphere

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SUMMARY

The buoyant force acting on a sphere with a radius of 10.0 cm, partially submerged in water, is calculated using the formula F = pvg, where p is the density of water (1000 kg/m³) and v is the volume of the submerged part of the sphere. The correct volume to use is that of a spherical cap, not half the volume of the sphere. After recalculating, the buoyant force is determined to be 6.42 N, aligning with the book's answer.

PREREQUISITES
  • Understanding of buoyancy principles
  • Familiarity with the formula F = pvg
  • Knowledge of spherical geometry, specifically spherical caps
  • Basic arithmetic and calculator skills
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  • Study the concept of buoyancy and Archimedes' principle
  • Learn to calculate the volume of a spherical cap
  • Explore the implications of density in buoyancy calculations
  • Practice problems involving buoyant forces on various shapes
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Carrie
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Homework Statement


A sphere of radius 10.0 cm floats in equilibrium partially submerged in water with its lowest point 5.00 cm below the water's surface.

(a) What is the buoyant force acting on the sphere?

Homework Equations


F = pvg

The Attempt at a Solution


F= 1000 * v * 9.8

V= 4/3*pi*(r)^3 and then I multiplied this by 1/2 because half of it is submerged.

F= 1000 * 1/2(4/3*pi*(.1)^3) * 9.8
F= 202 N, but the answer is 6.42 N, so that is very wrong.Thank you!
 
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Carrie said:

Homework Statement


A sphere of radius 10.0 cm floats in equilibrium partially submerged in water with its lowest point 5.00 cm below the water's surface.

(a) What is the buoyant force acting on the sphere?

Homework Equations


F = pvg

The Attempt at a Solution


F= 1000 * v * 9.8

V= 4/3*pi*(r)^3 and then I multiplied this by 1/2 because half of it is submerged.

F= 1000 * 1/2(4/3*pi*(.1)^3) * 9.8
F= 202 N, but the answer is 6.42 N, so that is very wrong.Thank you!
Check your arithmetic. I don't get your answer or the book's answer, either.
 
SteamKing said:
Check your arithmetic. I don't get your answer or the book's answer, either.
I think I might have messed up putting it in my calculator, because now I'm getting 20.5 N.
 
The sphere's radius is 10 cm. The lowest point is 5 cm below the water's surface. Sketch it.
 
Carrie said:
I think I might have messed up putting it in my calculator, because now I'm getting 20.5 N.
Closer, but still not what I calculated.
 
Okay, I sketched it and now I'm wondering if I use half that radius of 10 cm because it's half submerged. So:

F= 1000 * 1/2(4/3*pi*(.05)^3) * 9.8 = 5.13 N. I'm not sure if I'm going off in the wrong direction now.
 
Carrie said:
Okay, I sketched it and now I'm wondering if I use half that radius of 10 cm because it's half submerged. So:

F= 1000 * 1/2(4/3*pi*(.05)^3) * 9.8 = 5.13 N. I'm not sure if I'm going off in the wrong direction now.
No, the sketch is very helpful here. You want to find the volume of part of a sphere, what is called a spherical cap, like this (the blue region would be submerged):

15e369cd-befe-4b1c-bc5e-269ae7a025a7.png
https://en.wikipedia.org/wiki/Spherical_cap

I think I misread the problem like you did in my initial attempt at calculation, so the book answer could be correct.
 
Oh, that makes sense! Thank you for your help!
 

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