C++ Dice rolls: Counting number of rolls that equals six or seven. ()

[carl123]

1) Calculates the number of times the sum of the randomly rolled dice equals each possible value from 2 to 12.

2) Repeatedly asks the user for the number of times to roll the dice, quitting only when the user-entered number is less than 1. Hint: Use a while loop that will execute as long as numRolls is greater than 1. Be sure to initialize numRolls correctly.

3) Prints a histogram in which the total number of times the dice rolls equals each possible value is displayed by printing a character like * that number of times, as shown below.Dice roll histogram:

2: ******
3: ****
4: ***
5: ********
6: *******************
7: *************
8: *************
9: **************
10: ***********
11: *****
12: ****#include <iostream>
#include <cstdlib>

using namespace std;

int main(){
int i = 0; // Loop counter iterates numRolls times
int numRolls = 0; // User defined number of rolls
int numSixes = 0; // Tracks number of 6s found
int numSevens = 0; // Tracks number of 7s found
int die1 = 0; // Dice values
int die2 = 0; // Dice values
int rollTotal = 0; // Sum of dice values

count << "Enter number of rolls: " << endl;
cin >> numRolls;

srand(time(0));

if (numRolls >= 1) {
// Roll dice numRoll times
for (i = 0; i < numRolls; ++i) {
die1 = rand() % 6 + 1;
die2 = rand() % 6 + 1;
rollTotal = die1 + die2;

// Count number of sixs and sevens
if (rollTotal == 6) {
numSixes = numSixes + 1;
}
else if (rollTotal == 7) {
numSevens = numSevens + 1;
}
count << endl << "Roll " << (i + 1) << " is "
<< rollTotal << " (" << die1
<< "+" << die2 << ")";
}

// Print statistics on dice rolls
count << endl << endl;
count << "Dice roll statistics:" << endl;
count << "6s: " << numSixes << endl;
count << "7s: " << numSevens << endl;
}
else {
count << "Invalid rolls. Try again." << endl;
}

return 0;
}

 

[Evgeny.Makarov]

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