MHB -c6. Find the GCF and the LCF of A and B.

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The discussion focuses on finding the greatest common factor (GCF) and least common multiple (LCM) of two numbers A and B, expressed as products of powers of primes. The correct GCF is determined to be 2^1 * 3^1 * 11^2 * 13^1, while the LCM is calculated as 2^3 * 3^3 * 5^3 * 7^3 * 11^2 * 13^3. Participants clarify that the GCF includes the lowest powers of common prime factors, while the LCM incorporates the highest powers. Misunderstandings about the definitions of GCF and LCM are addressed. The final results for GCF and LCM are emphasized as critical for understanding the relationship between the two numbers.
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Find the greatest common factor and the least common multiple of A and B.
Write your answers as a product of powers of primes in increasing order.
$A=2^3 3 \cdot 5^3 \cdot 11^2 \cdot 13 $
$B = 2 \cdot 3^3 \cdot 7^3 \cdot 11^2 \cdot 13^3 $
$GCF(A,B) = \boxed{?}$
$LCM(A,B) = \boxed{?}$

ok apparently this is just by observation
but its kinda subtle so I went with $GCF(A,B) = \boxed{11^2}$ $LCM(A,B) = \boxed{2}$
hopefully
 
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I am afraid you are misunderstanding "greatest common factor". That is not a single prime that is in both numbers, it is the largest number that evenly divides both. I see that A has [math]2^3[/math] as a factor and B has 2 as a factor so the GCF has 2 as a factor. A has 3 as a factor and B has [math]3^3[/math] so the GCF has 3 as a factor. A has [math]5^3[/math] as a factor but B does not have a power of 5 as a factor so the GCF does not have a power of 5 as a factor. B has [math]7^3[/math] as a factor but A does not have a power of 7 as a factor so the GCF does not have a power of 7 as a factor. Both A and B have [math]11^2[/math] as a factor so the GCF has [math]11^2[/math] as a factor. A has 13 as a factor and B has [math]13^3[/math] as a factor so the GCF has13 as a factor.

The GCF is [math](2)(3)(11^2)(13)[/math]

For the GCF we took the lowest power of each prime. For the LCM (least common multiple) take the highest power. The LCM of A and B is [math](2^3)(3^3)(5^3)(7^3)(11^2)(13^3)[/math].
 
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