The rotational inertia for a diver in a pike position is about 15.5 kg m2; it is only 8.0 kg m2 in a tucked position (the figure above).
(a) If the diver gives himself an initial angular momentum of 106 kg m2/s as he jumps off the board, how many turns can he make when jumping off a 10.0-m platform in a tuck position? [Hint: Gravity exerts no torque on the person as he falls; assume he is rotating throughout the 10.0 m dive.]
(b) How many in a pike position?
n= (wf/2Pie) t
The Attempt at a Solution
The teacher mildly went over this problem in class. These are the eqns he gave us. I tried to solve for wf and substituted that answer in the second eqn to find the number of turns in time t, which i calculated thru the eqn :
h=vit + 1/2 at2
I really have NO idea how to do this problem, i only know these eqns from wat the instructor provided. If you can please teach me how to go about solving the problem and understanding it, i would really truly appreciate it!! Thanks!