Calculate "a" in c=sum_i( ( p(i)^a ) * b(i) ) / sum_i( p(i)^a )

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SUMMARY

The equation c = sum_i( ( p(i)^a ) * b(i) ) / sum_i( p(i)^a ) is used to calculate the variable "a" when "c", "b(i)", and "p(i)" are known. The transformation of the equation leads to the form sum p_i^a(c - b_i) = 0, which indicates that the solution for "a" requires further data or constraints. The discussion emphasizes the challenge of deriving "a" analytically without additional information on the variables involved.

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dalves
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In the following equation:

c = sum_i( ( p(i)^a ) * b(i) ) / sum_i( p(i)^a )

"c", "0 <= p(i) < 1" and "b(i)" are known.
How do I calculate "a"?
 
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dalves said:
In the following equation:

c = sum_i( ( p(i)^a ) * b(i) ) / sum_i( p(i)^a )

"c", "0 <= p(i) < 1" and "b(i)" are known.
How do I calculate "a"?



It's really hard to understand what you really meant without LaTeX, but if you meant

[itex]\displaystyle{c=\frac{\sum p_i^a b_i}{\sum p_i^a}\Longrightarrow \sum p_i^a(c-b_i)=0}[/itex] ...and this is as far as I can go without any further data.

DonAntonio
 
DonAntonio said:
It's really hard to understand what you really meant without LaTeX, but if you meant

[itex]\displaystyle{c=\frac{\sum p_i^a b_i}{\sum p_i^a}\Longrightarrow \sum p_i^a(c-b_i)=0}[/itex] ...and this is as far as I can go without any further data.

DonAntonio

That is correct, I totally agree. The only further data is that "b(i)", "0 <= p(i) < 1" and "c" are known. I was hoping to be able to calculate "a" ... analytically.
 

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