## \mu~\to e~ \gamma ## decay width and neutrino propagator

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Safinaz
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Hi all,

I'm studying ## \mu \to e~ \gamma ## decay from cheng & Lie' book " gauge theory of elementary particles ". In Equation (13.84), he wrote the neutrino propagator
## \sum_i \Big ( \frac{U^{*}_{ei} U_{\mu i}}{(p+k)^2-m_i^2} \Big), ##
(where the sum taken over neutrinos flavors) in the form:

##\sum_i U^{*}_{ei} U_{\mu i} \Big ( \frac{1}{(p+k)^2} + \frac{m_i^2}{[(p+k)^2]^2} + ... \Big) ##
##= \sum_i \frac{U^{*}_{ei} U_{\mu i} m_i^2}{[(p+k)^2]^2} + ...##

Do anyone know how did he drive this ? Then he write that:

the leading term vanishes, ## \sum_i U^{*}_{ei} U_{\mu i}##, reflecting the GIM cancellation mechanism.

I can't get this statement .. Thanks,
 
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Safinaz said:
where the sum taken over neutrinos flavors
No, the sum should be taken over the neutrino masses. The flavour eigenstates do not have definite masses.

Safinaz said:
Do anyone know how did he drive this ?

Just expand the quotient for small ##m_i##.

Safinaz said:
Then he write that:

the leading term vanishes, ## \sum_i U^{*}_{ei} U_{\mu i}##, reflecting the GIM cancellation mechanism.

I can't get this statement ..,

It follows directly from the unitarity of ##U##. It is the ##\mu##-##e## element of ##U U^\dagger = 1##.
 
Hi, thanks for replying:

Orodruin said:
Just expand the quotient for small ##m_i##.

Can you please write the general form, like for instance taylor expansion, it seems I'm not so good in math !

Orodruin said:
It follows directly from the unitarity of U. It is the ##\mu-e## element of ##U U^\dagger = 1##.

Actually this still not clear for me , ##\sum_i U^{*}_{ei} U_{\mu i} ## is multiplied by the first term ## \frac{1}{(p+k)^2} ## as well as the second term ## \frac{m_i^2}{[(p+k)^2]^2} ##, so why the first one which has been ignored .. also what's GIM mechanism and he says due to this mechanism this first leading term vanishes ..
 
Safinaz said:
Can you please write the general form, like for instance taylor expansion, it seems I'm not so good in math !

$$
\frac{1}{1+x} = 1 - x + x^2 + \ldots
$$

Safinaz said:
Actually this still not clear for me , ##\sum_i U^{*}_{ei} U_{\mu i} ## is multiplied by the first term ## \frac{1}{(p+k)^2} ## as well as the second term ## \frac{m_i^2}{[(p+k)^2]^2} ##, so why the first one which has been ignored .. also what's GIM mechanism and he says due to this mechanism this first leading term vanishes ..

The first term ## \frac{1}{(p+k)^2} ## is independent of ##i## and can be taken out of the sum. The second term is not independent of ##i##.
 
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