Calculate Bacteria Growth Rate: Doubling Time

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SUMMARY

The discussion focuses on calculating the doubling time of bacteria growth, starting with an initial population of 2000 bacteria that increases to 2500 in one hour. The growth rate is determined using the formula rate = (final population)/(initial population), resulting in a rate of 1.25. To find the doubling time, the equation Time to double = 0.693/((ln(1+r))^t) is applied, where 'r' is the growth rate. The correct application of these formulas leads to the determination of the doubling time for the bacteria.

PREREQUISITES
  • Understanding of exponential growth models
  • Familiarity with natural logarithms (ln)
  • Basic algebra for solving equations
  • Knowledge of bacterial growth dynamics
NEXT STEPS
  • Study the mathematical derivation of the exponential growth formula N=N0e^(kt)
  • Learn how to apply natural logarithms in growth rate calculations
  • Explore the implications of different growth rates on bacterial populations
  • Investigate real-world applications of bacterial growth models in microbiology
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Students in biology or microbiology courses, educators teaching population dynamics, and anyone interested in mathematical modeling of biological processes.

stegz
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Homework Statement


A beaker contained 2000 bacteira. one hour later the beaker contained 2500 bacteria. What is the doubling time of the bacteria?


Homework Equations


rate = (distance)/(time)
Time to double = .693/((ln(1+r))^t)


The Attempt at a Solution


rate = 2500/2000
My biggest problem is trying to find the rate, I used this at first, but think it is giving me the wrong answer. I know how to finish the problem, i just need help finding the rate. Thanks!
 
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You should think in terms of N=N0ekt.
 

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