Calculate CaCO3 Mass: Stoichiometry Help for Decomposition Reaction

  • Thread starter Thread starter Soaring Crane
  • Start date Start date
  • Tags Tags
    Stoichiometry
Click For Summary
SUMMARY

The discussion focuses on calculating the mass of calcium carbonate (CaCO3) from the decomposition reaction that produces carbon dioxide (CO2) and calcium oxide (CaO). The calculation shows that 1.5432 g of CO2 corresponds to 3.5097 g of CaCO3 using stoichiometric relationships. To determine the percentage by mass of CaCO3 in a 5.768 g sample, the correct method is to divide the mass of CaCO3 (3.5097 g) by the total mass of the sample (5.768 g) and multiply by 100, yielding approximately 60.9% CaCO3.

PREREQUISITES
  • Understanding of stoichiometry and molar conversions
  • Familiarity with the decomposition reaction of calcium carbonate
  • Knowledge of molar masses (e.g., CO2: 44.01 g/mol, CaCO3: 100.09 g/mol)
  • Basic skills in percentage calculations
NEXT STEPS
  • Study stoichiometric calculations in chemical reactions
  • Learn about the thermal decomposition of carbonates
  • Explore molar mass determination and its applications
  • Investigate methods for calculating percentage composition in mixtures
USEFUL FOR

Chemistry students, educators, and professionals involved in chemical analysis or laboratory work, particularly those focusing on stoichiometry and reaction calculations.

Soaring Crane
Messages
461
Reaction score
0
a. A sample of CaCO3 decomposes when heated to form calcium oxide and carbon dioxide. 1.5432 g of CO2 are released in the reaction. Find g of CaCO3 in the original sample.
CaCO3 --> CO2 + CaO

1.5432 g CO2*(1 mol of CO2/44.01 g) = 0.035065 mol of CO2*(1 mol CaCO3/1 mol CO2) = 0.035065 mol CaCO3

0.035065 mol CaCO3*(100.09 g/ 1mol CaCO3) = 3.5097 g CaCO3??


b. The original sample was a mixture from which only CaCO3 released carbon dioxide. Calculate the percentage by mass of CaCO3 if original's sample mass was 5.768 g.


Do I divide 3.5097 g CaCO3/5.768 g * 100 or must I subtract the grams of CO2 from the original sample's mass?

Thanks.
 
Last edited:
Physics news on Phys.org
Any volunteers?

Thanks again.
 
Soaring Crane said:
a. A sample of CaCO3 decomposes when heated to form calcium oxide and carbon dioxide. 1.5432 g of CO2 are released in the reaction. Find g of CaCO3 in the original sample.
CaCO3 --> CO2 + CaO

1.5432 g CO2*(1 mol of CO2/44.01 g) = 0.035065 mol of CO2*(1 mol CaCO3/1 mol CO2) = 0.035065 mol CaCO3

0.035065 mol CaCO3*(100.09 g/ 1mol CaCO3) = 3.5097 g CaCO3??
That's correct.


b. The original sample was a mixture from which only CaCO3 released carbon dioxide. Calculate the percentage by mass of CaCO3 if original's sample mass was 5.768 g.


Do I divide 3.5097 g CaCO3/5.768 g * 100 or must I subtract the grams of CO2 from the original sample's mass?

Thanks.
This looks a little silly, but your first idea seems right.
 
all seemed right: (3.5097/5.768)*100 should do it.
 

Similar threads

Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
4K
Replies
5
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 6 ·
Replies
6
Views
14K
  • · Replies 3 ·
Replies
3
Views
10K
Replies
1
Views
5K
Replies
9
Views
3K