Given that sin(θ) = y/r, that we're in Quadrant III, and that x2 + y2 = r2, you should be able to find x, and from that, cos(θ).
Then use the cosine half-angle identity
[tex]\cos \left( \frac{\theta}{2} \right) = \pm \sqrt{\frac{1 + \cos \theta}{2}}[/tex]
to find cos(θ/2). Since π < θ < 3π/2, you know the range of values that θ/2 lie in, so that will tell you whether the square root should be positive or negative.