Calculate Displacement in a Police Car Scenario: Juction 4 to Accident

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SUMMARY

The discussion focuses on calculating the displacement of a police car traveling from Junction 4 to an accident site. The car travels 12 km in one direction and then 8 km in the opposite direction, resulting in a net displacement of 4 km. The velocities during these segments are 30 m/s and 25 m/s, respectively. Additionally, participants discuss how to sketch a displacement-time graph, emphasizing that time is the independent variable plotted on the x-axis.

PREREQUISITES
  • Understanding of basic physics concepts such as displacement and velocity
  • Familiarity with displacement-time graphs
  • Knowledge of constant speed calculations
  • Ability to interpret gradients in graphical representations
NEXT STEPS
  • Learn how to construct displacement-time graphs for varying velocities
  • Study the principles of acceleration and deceleration in motion
  • Explore the concept of net displacement in multi-segment journeys
  • Practice problems involving displacement calculations in physics
USEFUL FOR

This discussion is beneficial for students studying physics, particularly those focusing on kinematics, as well as educators seeking to explain displacement and graphing concepts effectively.

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Homework Statement



A police car joins a straight motorway at Juction 4 and travels for 12 km at a constant speed for 400 seconds, then it leaves at junction 5 and rejoins on the opposite side and travels for 8 km at a constant speed for 320 (s) to reach an accident.

Calculate the displacement from junction 4 to the accident.


Homework Equations



No idea, I really need explanation on how to work this out, a link and other practice questions would be really helpful.

The Attempt at a Solution



I have not attempted it, but I know that with displacement graphs, deceleration is a downwards curve and acceleration is a curve with increasing gradient. When an object reverses its velocity changes, however I see no relevance of this to my question.

Please HELP! :confused:
 
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Well from the starting point, the car traveled 12 km in one direction (and as I understand it) it then traveled 8km in the opposite direction. So if you take the first direction as positive, then the opposite direction would be a negative direction.

Therefore the car first traveled +12km and then -8km.

Just sum up the journeys to get the displacement in this plane.
 
OK so just simply 12 - 8 = 4 km

OK, so next question is to sketch a displacement-time graph for it.

So, I know the velocity on each side of the motorway is 30 m/s and 25 m/s in the opposite direction. So how do I sketch the graph ?

Does I make a table of values or something ?
 
Not necessarily. From the name you know that one axis will be displacement and the other will be time.
Time is the independent variable so by nature you'd put it on the x axis.

When you think about it a little, you can see as time goes on the displacement (from the origin) will increase linearly (constant velocity) and then when it turns around, it will decrease linearly.

The rate of increase/decrease (gradient) is rise over run. When you divide rise (displacement) by run (time) you will see that you get velocity.
So your gradients will be 30 and 25 respectively.
 

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