Calculate distance from a point 100m from a plane given two angles

  • Thread starter Thread starter robertadamplant
  • Start date Start date
  • Tags Tags
    Angles Plane Point
Click For Summary
The discussion centers on calculating the distance from a point 100 meters above a horizontal plane, given two angles of 8 degrees and 21 degrees. Participants note that the original question lacks sufficient information and clarity, particularly regarding the concept of a "plane of 100 meters." It is suggested that the inquiry may actually involve finding the height of a triangle with a base of 100 meters and the specified angles. A diagram is recommended for better understanding, and there is a hint that this might be related to a schoolwork problem. Clearer parameters are necessary to provide a meaningful solution.
robertadamplant
Messages
1
Reaction score
0
I am looking for a formula.

From a horizontal plane of 100 meters; If angle on the left is 8 degrees and the angle on the right is 21 degrees at what distance from the centre of the horizontal plane will these two angles converge?
 
Last edited by a moderator:
Physics news on Phys.org
Your question above does not contain enough information for an answer. We will need more parameters to provide any meaningful answer.
 
Last edited by a moderator:
This is not differential geometry.

There is no such thing as a 'plane of 100 metres', and planes do not have a centre.

I think the question you meant to ask is "a triangle has a base of 100 metres and sides at angles 8 degrees and 21 degrees from the base; what is the height of the triangle?". If this is not what you meant or you are unsure, draw a diagram.
 
  • Like
Likes DaveC426913
The working out suggests first equating ## \sqrt{i} = x + iy ## and suggests that squaring and equating real and imaginary parts of both sides results in ## \sqrt{i} = \pm (1+i)/ \sqrt{2} ## Squaring both sides results in: $$ i = (x + iy)^2 $$ $$ i = x^2 + 2ixy -y^2 $$ equating real parts gives $$ x^2 - y^2 = 0 $$ $$ (x+y)(x-y) = 0 $$ $$ x = \pm y $$ equating imaginary parts gives: $$ i = 2ixy $$ $$ 2xy = 1 $$ I'm not really sure how to proceed from here.

Similar threads

Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
20
Views
4K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K