Calculate Efficiency of a Falling Mass System: Homework Help and Solution - 82%

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Homework Help Overview

The discussion revolves around calculating the efficiency of a system that utilizes a falling mass to move a box along a desk. The problem involves understanding the energy input and output in the context of gravitational potential energy and kinetic energy, with specific weights and distances provided for both the box and the falling mass.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formulas for energy input and output, questioning whether they have been applied correctly. There is a suggestion that friction needs to be considered, and some participants explore the implications of mass ratios on efficiency calculations.

Discussion Status

The discussion is active, with participants providing feedback on calculations and questioning the assumptions made regarding friction and the application of gravitational acceleration. There is no explicit consensus on the correct approach, but several lines of reasoning are being explored.

Contextual Notes

Participants note potential issues with unit conversions and the need for clarity on the role of friction in the efficiency calculation. There is also mention of the relationship between gravitational potential energy and kinetic energy in the context of the problem.

UnnamedOne
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Homework Statement


Question:
Calculate the efficiency of a system that uses a falling mass to move a box along the desk.
Given (helps to see picture):
Weight of (sliding) box = 164g
Weight of (falling) mass = 200g
Distance of board (platform) = 88cm
Time (avg) = 6s
(anything missing? I can get it, just point it out [its a lab])

Homework Equations


Efficiency = (energy output/energy input) x 100%

The Attempt at a Solution


Ei = mad
= (0.2kg)(9.8kg/N)(0.88m)
= 1.7J
Eo= mgh
= (0.164kg)(9.8kg/N)(0.88m)
= 1.4J
E% = (Eo/Ei) x 100%
= (1.4J/1.7J) x 100%
= 82%

Picture I made:

w.w.w.i235.photobucket.com/albums/ee170/ShadowedIMG/Homework.png
(cant post links)

Any input to anything would be very helpful, and thanks for your time.
 
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You need to know friction. Without friction, the efficiency is 100%.

UPDATE: No, never mind. That's wrong. What you have is right, except that the formulas for Ei and Eo are reversed. (but friction will decrease the efficiency)
 
Last edited:
well this problem sort of seems to be solved wrong because of the simple fact the effeciency of the system is merely a factor of [itex]\frac{E_i}{E_o}[/itex] By your calculations, if you go to see, acceleration, the distance moved all cancel out and hence the effeciency is given by the ratios of the two masses. Hence, by just adjusting the masses of the two systems, you can raise the effeciency of the system to more than 100%.

although i am not sure how this contradiction occurs, and the formula which is W = Fd seems to be used rightly.. the loss in the GPE of the falling mass MUST equal the kinetic energy acquired by the moving mass.
 
Hi UnnamedOne,

UnnamedOne said:

Homework Statement


Question:
Calculate the efficiency of a system that uses a falling mass to move a box along the desk.
Given (helps to see picture):
Weight of (sliding) box = 164g
Weight of (falling) mass = 200g
Distance of board (platform) = 88cm
Time (avg) = 6s
(anything missing? I can get it, just point it out [its a lab])

Homework Equations


Efficiency = (energy output/energy input) x 100%


The Attempt at a Solution


Ei = mad
= (0.2kg)(9.8kg/N)(0.88m)
= 1.7J
Eo= mgh
= (0.164kg)(9.8kg/N)(0.88m)
= 1.4J

I think you have a problem with a value here. (Your units of kg/N need to be N/kg.) Using 9.8 N/kg is correct for the g in the energy input mgh; however, 9.8 is not correct for the acceleration of the sliding mass. It will always be less than 9.8 (even if there is no friction).

That's why the efficiency here will always be less than 100% even if there is no friction; gravity is doing work on both blocks, but you only want to find the fraction of gravity's work that is going to the sliding block. (Using [itex]mad[/itex] for the energy output would include frictional heating as part of the energy output.)
 

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