Calculating Efficiency and Power in a Belt Drive: A Homework Guide"

[nettie2311]

Homework Statement

A belt drive transmits 56kW from the driver pulley to the driven pulley. If 2.5kW is lost in belt friction, calculate:

1. kW's supplied by driver pulley

2. efficiency of the belt drive expressed as a percentage.

Homework Equations

%Efficiency = (power output/power input) x 100%

The Attempt at a Solution

I'm really not sure how to tackle this question, if anyone can help it would be greatly appreciated.

Thanks

 

[L2E]

power in = 56kW
Power loss = 2.5kW
power out = power in - power loss

for efficiency you can just use your equation.

Try it right now!

 

[berkeman]

Homework Statement

A belt drive transmits 56kW from the driver pulley to the driven pulley. If 2.5kW is lost in belt friction, calculate:

1. kW's supplied by driver pulley

2. efficiency of the belt drive expressed as a percentage.

Homework Equations

%Efficiency = (power output/power input) x 100%

The Attempt at a Solution

I'm really not sure how to tackle this question, if anyone can help it would be greatly appreciated.

Thanks

copying...

 

[L2E]

Reading was definitely not my strong point last night. Just want to change what I wrote.

if 56kW was supplied to the driven pulley, 56kW is the output.
the input is unknown (well it's 58.5kW)