Calculate Energy and Velocity of Thrown Objects: Beach Ball and Fastball

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    Energy Physcis
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Homework Help Overview

The discussion revolves around calculating energy and velocity for two thrown objects: a beach ball and a fastball. The beach ball is thrown vertically with an initial speed and height, while the fastball is thrown horizontally with specified speed and height. Participants are exploring various aspects of kinematics and energy conservation in these scenarios.

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  • Mixed

Approaches and Questions Raised

  • Participants are attempting to calculate maximum height and impact speed for the beach ball, as well as energy calculations for the fastball. Some are questioning the effects of air resistance and how it alters the outcomes.

Discussion Status

Some participants have begun to share their calculations, while others express confusion about the problem setup and the necessary steps to take. There is an indication that attempts are being made to engage with the problem, but clarity is still needed.

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Participants are reminded to show their work as part of the homework guidelines, which may influence the depth of their responses and the nature of the discussion.

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1 A beach ball is thrown straight up with a speed of 10m/s from a point 2 m above the ground
a) Assuming no air reistance, calculate how far up the ball will go
b)At what speed will the ball eventually hit the ground?
c) If the air resistance exerts a constant force fo 10N during the journey, calculate the new maximum height and maximum speed of the ball.

2. A pitcher throws a fastball, off target, at a speed of 90 km/h and hits home plate. The ball of mass 0.14 kg is 2.2 m above the ground when it leaves the pither's hand
a)What is the total gravitational and kinetic energy of the ball at the time of release?
b) What is the ball's kinetic energy when it reaches home plate?
c) How fast is the ball moving when it collides with the home plate?
 
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As this is homework, you'll need to show an attempt first.

What are your thoughts on this?
 
honestly I'm lost
 
for 1 a) i got 50m
by first finding the time
then the distance
t=2/10
=0.2

d=v/t
=10/0.2
 

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