Calculate Force on 10m x 12m Roof in Kansas

  • Thread starter Thread starter DeltaIceman
  • Start date Start date
  • Tags Tags
    Force
Click For Summary
SUMMARY

The discussion focuses on calculating the force exerted on a 10m x 12m roof in Kansas due to wind pressure. The relevant equations include Bernoulli's principle, specifically p1A1v1=p2A2v2 and P2 + (0.5)p(v2^2)=P1 + (0.5)p(v1^2), along with the pressure-force relationship P=F/A. The user initially struggled with determining the pressures P1 and P2 but ultimately realized the solution was simpler than anticipated, emphasizing the importance of taking breaks to clear one's mind when faced with complex problems.

PREREQUISITES
  • Understanding of Bernoulli's principle and fluid dynamics
  • Familiarity with pressure calculations in physics
  • Basic algebra for manipulating equations
  • Knowledge of units of measurement, specifically square meters for area
NEXT STEPS
  • Study Bernoulli's equation in detail to understand fluid flow and pressure relationships
  • Learn how to calculate wind pressure on structures using ASCE 7 standards
  • Explore practical applications of fluid dynamics in engineering
  • Practice solving similar problems involving atmospheric pressure and force calculations
USEFUL FOR

This discussion is beneficial for physics students, engineers, and anyone interested in understanding the effects of wind pressure on structures, particularly in residential settings.

DeltaIceman
Messages
14
Reaction score
0

Homework Statement


Dorothy is up on her 10.0m by 12.0m roof enjoying the view of Kansas. Suddenly, a strong wind blows down her ladder, leaving her stranded. She knows that a high wind reduces the air pressure on the roof, and that there is a danger that the atmospheric pressure inside the house will blow the roof off. As the wind reaches a speed of 27.5m/s, she calls to her Auntie Em for help. Calculate the force on the roof.


Homework Equations


p1A1v1=p2A2v2
P2 + (.5)p(v2^2)=P1 + (.5)p(v1^2)
P=F/A

The Attempt at a Solution


I have been looking at this problem for awhile now and I'm not to sure on where to start. I know you can find the area of the roof by multiplying the values. Getting you a 120 m^2. I thought maybe you could use the second equation I listed. And since the velocity in the house is 0 you could set P1 = P2 + .5(v2^2)p but I don't know how to find P1 or P2... So I guess I'm just kinda at a loss. Can someone push me in the right direction.
 
Physics news on Phys.org
Sorry for the question everyone. I figured out the answer. I was overcomplicating the problem and it was just stressing me out but I took a break and came back and realized it wasn't hard at all.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
Replies
0
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 19 ·
Replies
19
Views
5K
Replies
1
Views
6K
Replies
1
Views
4K