Calculate Isentropic Efficiency: Tips & Tricks

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SUMMARY

The discussion focuses on calculating the isentropic efficiency of an expander in an Organic Rankine Cycle (ORC) using experimental data of inlet and outlet temperatures and pressures. Participants emphasize the importance of determining actual enthalpy at the expander exit, particularly when the exit conditions are in a two-phase zone. The formula for isentropic efficiency is provided: $$\eta_{isent} = {H_{in} - H_{out}\over H_{in} - H_{isent}}$$, where enthalpies can be derived from steam tables. The challenge lies in accurately determining the enthalpy in cases where the quality or dryness fraction is unknown.

PREREQUISITES
  • Understanding of isentropic processes in thermodynamics
  • Familiarity with steam tables for enthalpy values
  • Knowledge of the Rankine cycle and its components
  • Basic principles of thermodynamic efficiency calculations
NEXT STEPS
  • Research how to use steam tables to find enthalpy values for different phases
  • Learn about calculating quality and dryness fraction in two-phase systems
  • Explore advanced topics in thermodynamic efficiency, specifically for turbines
  • Investigate software tools for thermodynamic cycle analysis, such as EES (Engineering Equation Solver)
USEFUL FOR

Engineers, thermodynamic analysts, and researchers involved in the design and optimization of Organic Rankine Cycles and turbine efficiency calculations.

y2j
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Hi
can anyone help me about the following ?
if I have the experimental data of inlet and outlet of expander (temperature and pressure) working in ORC.
Now if I want to find the Isentropic efficiencie :
the Isentropic expansion can be found by (entropy in = entropy out)
but how to find the actual enthalpy at expander exit of actual expansion
(i.e. I can consider it in the mixture or superheated phase?)
thank you
 
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entropy in = entropy out gives you an enthalpy. Enthalpy difference * efficiency gives you a new enthalpy. Pressure and enthalpy give you a temperature (or a composition at saturation).

See e.g. here ( I Googled "isentropic efficiency turbine" and looked at the first image)
 
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thanks for reply
but i am not have the Isentropic Efficiency

I am only have pressure and temperature of experimental system and I would like to have the Isentropic Efficiency if the exit conditions locate in tow phase zone
 
Then you work backwards from the enthalpy observed...
 
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I don't understated you
BvU said:
Then you work backwards from the enthalpy observed...
what do you mean?
thanks again
 
Perhaps you should post your work so far.

You have enthalpy in ##H_{in}##

entropy in = entropy out gives you an enthalpy under isentropic conditions ##H_{isent}##

observed enthalpy ##H_{out}##

$$\eta_{isent} = {H_{in} - H_{out}\over H_{in} - H_{isent}}$$
 
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I am not have the Isentropic Efficiency
I am only have pressures and temperatures at inlet and outlet of the
turbine
how can obtain Isentropic Efficiency in this case
 
thanks for attention
 
Is it clear now ?
 
  • #10
not yet
 
  • #11
Writing the same text in red does not help me to understand where you have a problem. Can you post your work so far ?
 
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  • #12
OK
I have an experimental data of inlet and outlet conditions of turbine (temperature and pressure ) working in a rankine cycle
when the exit condition from turbine in saturated phase
how I can find the actual enthalpy at exit (##H_{out}##)and that used to find the Isentropic Efficiency
 
  • #13
No need to get desperate...
Enthalpies can be looked up in a steam table. Do you have that available in some form or other ?
 
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  • #14
Enthalpies in the mixture zone given for vapor and liquid
in this case to find Enthalpy we must have another parameter is (quality x) or dryness fraction
and the later I have not
 
  • #15
I agree. That makes it difficult to get the correct value of ##\eta##. All I can imagine is that you assume no water comes out of the tubine, only steam...
 

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