MHB Calculate Length of Median on Trapeze (48 cm)

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To calculate the length of the median of a trapeze with a perimeter of 48 cm and non-parallel sides measuring 15 cm and 13 cm, the sum of the lengths of the two parallel bases is determined to be 20 cm. The median is defined as the average of these two base lengths. The discussion clarifies that the median is not simply the sum but rather the mean of the base lengths. The final answer for the median length is derived from this calculation. Understanding the properties of trapezes is essential for solving such problems.
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The two non-parallel sides of the trapeze are 15 cm and 13 cm, the perimeter is 48 cm. Find the length of the median.
I don't know anything about trapezes can someone expain how to do this?
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GVdig said:
The two non-parallel sides of the trapeze are 15 cm and 13 cm, the perimeter is 48 cm. Find the length of the median.
I don't know anything about trapezes can someone expain how to do this?

the median length is the average of the two bases ... let $a$ and $b$ represent the length of each base.

$(a+b) + 13+15 = 48 \implies (a+b) = 20$

can you finish?
 
I don't think I can, what is 20 exactly?
 
GVdig said:
I don't think I can, what is 20 exactly?

20 is the sum of the lengths of the two parallel bases ... the median, or mid-segment, is the average (mean) of those two base lengths.
 
So that's the final answer then.
 
GVdig said:
So that's the final answer then.

no ...
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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