Calculate Local g on Small Planet: 3.70g Wire, 3.00kg Mass, 43.6ms Pulse

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SUMMARY

The discussion focuses on calculating the local gravitational acceleration (g) on a small planet using a wire and a suspended mass. The wire has a mass of 3.70 g and a length of 1.60 m, with a 3.00 kg mass suspended from it. A pulse takes 43.6 ms to travel the length of the wire. The incorrect formula used was g = length * mstring / (mweight * t^2), which led to an erroneous result of 0.001. The correct approach requires careful consideration of the tension in the wire and the proper application of the formula.

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An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large mass suspended from it. Assume that the wire has a mass of 3.70 g and a length of 1.60 m and that a 3.00 kg mass is suspended from it. A pulse requires 43.6 ms to traverse the length of the wire. Calculate the local g from these data. (You may neglect the mass of the wire when calculating the tension in it.)

I tried to solve the qustion by doing g= length * mstring/ ( mweight*t^2) and i got .001 but the answer is wrong
 
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Hi lulu16,


lulu16 said:
An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large mass suspended from it. Assume that the wire has a mass of 3.70 g and a length of 1.60 m and that a 3.00 kg mass is suspended from it. A pulse requires 43.6 ms to traverse the length of the wire. Calculate the local g from these data. (You may neglect the mass of the wire when calculating the tension in it.)

I tried to solve the qustion by doing g= length * mstring/ ( mweight*t^2) and i got .001 but the answer is wrong


I don't see how you are getting 0.001 as your answer. What numbers are you putting into your formula?
 

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