Measure the acceleration due to gravity on a distant planet

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Homework Help Overview

The discussion revolves around measuring the acceleration due to gravity on a distant planet using a ball suspended from a wire. The problem involves calculating the velocity of a transverse pulse traveling along the wire and subsequently determining the gravitational acceleration based on that velocity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of pulse velocity and question the original poster's approach to determining gravitational acceleration. There is a focus on clarifying the distinction between pulse speed and standing wave frequency.

Discussion Status

Some participants have provided feedback on the calculations, suggesting corrections and confirming the validity of revised values. There appears to be a productive exchange regarding the methodology used in the calculations.

Contextual Notes

The original poster expresses uncertainty about their calculations, indicating a need for clarification on where errors may have occurred. There is a mention of the mass of the wire being negligible compared to the mass of the ball, which may influence the assumptions in the calculations.

rayhan619
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Homework Statement



To measure the acceleration due to gravity on a distant planet, an astronut hangs a 0.055 kg ball from the end of a wire. the wire has a length of 0.95 n and a linear density of 1.2*10
^-14 kg/m. using electronic equipment, the astronaut measures the time for a transverse pulse to travel the length of the wire and obtains a value of 0.016 s. the mass of the wire is negligible compared to the mass of the ball.
a) draw a nice picture
b) calculate the velocity of the pulse
c)determine the acceleration due to gravity

Homework Equations



f = v/2L
v = (Mg/mu)^sq. root

The Attempt at a Solution



m = 0.055 kg
L = 0.95 m
mu = 1.2*10^-4 kg/m
T = 0.016 s

b)f = 1/0.016s = 62.5 hz
v = 2fL = 2*62.5 hz*0.95 m = 118.75 m/s

c)g = (v^2*mu)/M = {(118.75 m/s)^2*1.2*10^-4 kg/m}/0.055 kg = 30.77 m/s^2

i got both of them wrong. where did i screw up?
 
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rayhan619 said:
b)f = 1/0.016s = 62.5 hz
v = 2fL = 2*62.5 hz*0.95 m = 118.75 m/s
This is a pulse, not a standing wave. The speed of the pulse is simply distance/time.
 
a) i have attached the picture to check it.

so for b) v = L/t = 0.95 m/ 0.016 s = 59.38 ms^-1

and c) g = {(59.38 m/s)^2 * 1.2*10^-4 kg/m}/ 0.055 kg = 7.69 m?s^2.

right?
 

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Looks good to me.
 
appreciate it man
 

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