Calculate Mass of Sphere: ρ0 & R

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Homework Help Overview

The problem involves calculating the mass of a sphere with a density that varies with distance from its center, defined by the function ρ(r) = ρ0(1 − r/R). The original poster seeks to express the mass in terms of the constants ρ0 and R.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to set up an integral to find the mass by considering a spherical shell and integrating from 0 to R. Some participants suggest completing the integration and express uncertainty about how to handle the integration involving the density function.

Discussion Status

Participants are actively discussing the integration process and clarifying the setup of the problem. There is a focus on understanding the mathematical steps involved, particularly regarding the integration of the density function.

Contextual Notes

There appears to be some confusion regarding the integration limits and the interpretation of the density function in relation to the radius of the sphere.

~Sam~
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Homework Statement



The density of a sphere of radius R as a function of distance from the centre r is ρ(r) = ρ0(1 − r/R)
What is the mass of the sphere in terms of ρ0 and R?

Homework Equations



Volume of a Sphere=(4/3)piR3


The Attempt at a Solution



I'm somewhat confused by the question. To my understanding, I can determine the mass of the sphere by integrating from 0 to radius R. I would consider a spherical shell a distance r from the center and of thickness dr. Thus I integrate from 0 to R and get something like 4pir2(1-r/R)ρ(r)dr, which is the mass of the sphere. But I'm not sure if that's what is needed. Any ideas?
 
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dm = 4pir2(1-r/R)ρ(r)dr
Complete the integration. So
m = 4*pi*rho* intg(r^2*dr - r^3*dr/R) from zero to R.
 
rl.bhat said:
dm = 4pir2(1-r/R)ρ(r)dr
Complete the integration. So
m = 4*pi*rho* intg(r^2*dr - r^3*dr/R) from zero to R.

Huh, I'm not quite sure how the integration with (1-r/R) works...R would be the radius, and r would be the distance from centre...care to explain?
 
You have to integrate [ intg(r^2*dr - r^3*dr/R)] between 0 to R.
It is equal to [R^3/3 - R^3/4]
 

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