Calculate Mass of Water Vapor in NaHCO3 + HCl Reaction

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SUMMARY

The discussion focuses on calculating the mass of water vapor produced in the reaction between sodium bicarbonate (NaHCO3) and hydrochloric acid (HCl), which yields sodium chloride (NaCl), carbon dioxide (CO2), and water (H2O). The provided conditions include a volume of 39.5 L, a pressure of 18.65 mm Hg, and a temperature of 294 K, with 30.5 moles of water vapor generated. Participants discuss using the total pressure equation P(total) = P(a) + P(b) and the ideal gas law to derive the mass of water vapor, emphasizing the need for clarity in the problem statement.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Familiarity with the ideal gas law (PV=nRT)
  • Knowledge of gas pressure conversions (mm Hg to inHg)
  • Basic principles of partial pressures in gas mixtures
NEXT STEPS
  • Review the ideal gas law and its applications in calculating gas properties
  • Study the concept of partial pressures and Dalton's Law of Partial Pressures
  • Practice stoichiometric calculations involving gas reactions
  • Learn how to convert between different pressure units, specifically mm Hg and inHg
USEFUL FOR

Chemistry students, educators, and anyone involved in chemical reaction calculations or gas law applications.

blicker
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Homework Statement


Find the mass of water vapor.
this is the reaction: NaHCO3+HCl-->NaCl+CO2+H2O

V=39.5 L
P=18.65 mm Hg
T=294 K
n=30.5 mol H20 (g)
pressure of room= 29.68 inHg=753.87mm Hg

Homework Equations





The Attempt at a Solution


Would i have to use this equation P(total)=P(a)+P(b)
and if so, would P(total) equal to the pressure of the room?
then after that would i have to use the ideal gas law?
 
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What is the original wording of the question? Data - as you presented it - don't make much sense to me.
 

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