Calculating pH of Water After Adding HCl and NaOH

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Discussion Overview

The discussion centers on calculating the pH of water after the addition of 1M HCl and 1M NaOH, focusing on the implications of a neutralization reaction and the potential effects of ionic strength on pH.

Discussion Character

  • Homework-related, Technical explanation, Debate/contested

Main Points Raised

  • One participant asserts that the reaction between HCl and NaOH produces water and NaCl, suggesting that the pH remains unchanged due to neutralization.
  • Another participant agrees with the assertion that the pH does not change.
  • A different participant raises the consideration of ionic strength, indicating that it may affect the expected pH, particularly at an undergraduate level.
  • One participant emphasizes the original question regarding the pH, implying that the focus should remain on that aspect.

Areas of Agreement / Disagreement

While there is some agreement on the neutralization aspect, there is disagreement regarding the impact of ionic strength on the pH, indicating multiple competing views in the discussion.

Contextual Notes

Participants have not fully resolved the implications of ionic strength on pH, and there may be assumptions regarding the conditions under which the pH is being evaluated.

thercias
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Homework Statement


What will the pH be by adding 1M HCL and 1M NaOH to pure water?

Homework Equations


pH= -log[H+]

The Attempt at a Solution


Well, If we form the reaction formula we get
HCl + NaOH ---> H20 + NaCl

This is a neutralizing reaction, so the net effect produces just water. Therefore the pH doesn't change. Is this logic right?
 
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Correct.
 
Depends on whether you are expected to take ionic strength of the solution into effect, or not. That's typically at least undergraduate level though.
 
And don't forget the question was: what is the pH?
 

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