Calculate Max Acceleration Mass-Spring System: Vibration/SHM Help

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SUMMARY

The discussion focuses on calculating the maximum acceleration of a mass-spring system with a spring constant of 230 N/m, a mass of 0.50 kg, and an amplitude of 3.5 cm. The mechanical energy of the system is provided as 0.14 joules. To find the maximum acceleration, one must utilize the formula for angular frequency, ω, derived from the spring constant and mass, and apply it to the maximum displacement. The maximum acceleration can be calculated using the formula a_max = ω² * A, where A is the amplitude.

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  • Understanding of Hooke's Law and spring constant (k)
  • Knowledge of angular frequency (ω) in harmonic motion
  • Familiarity with the concepts of mechanical energy in oscillatory systems
  • Basic calculus for differentiation and second derivatives
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  • Learn how to derive angular frequency (ω) from spring constant (k) and mass (m)
  • Study the relationship between amplitude and maximum acceleration in harmonic motion
  • Explore the principles of mechanical energy conservation in mass-spring systems
  • Practice solving problems involving differential equations in simple harmonic motion
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Can anyone help me with this problem? Thank-you

1) A mass-spring system oscillates with an amplitude of 3.5 cm. The spring constant is 230 N/m and the mass is 0.50 kg. The
mechanical energy of the mass-spring system is 0.14 joules. Calculate the maximum acceleration of the mass-spring system.

I'm not sure what formula I would use... am I solving for g?
 
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The problem is asking for the maximum acceleration of the mass-spring system, and acceleration, a, = dv/dt.

One is given the spring constant, k, and mass, m, from which one may obtain the angular frequency,[itex]\omega[/itex], of the system.

One is also given the maximum amplitude.

Taking x(t) of the spring, which is the position of the mass from equilibrium, one can fine dx/dt, and d2x/dt2.
 

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