Calculate Moment of Inertia: Thin Rod, Length 3.14m, Mass 2.11kg

[ViewtifulBeau]

A uniform thin rod has a length 3.14 m and mass 2.11 kg. Find the moment of inertia in kg-m2 about an axis that is perpendicular to the rod and passes through the rod at a distance of 0.67 m from the end of the rod.

I know that if the axis was in the center of the rod the equation would be 1/12 * M *L^2 . M =mass L = length.

I don't know what to do with the axis being in a different place. is it the same eqation(doubt it) or the left half minus the right half or what?

 

[Pyrrhus]

Use the Parallel axis or Steiner's Theorem.

 

[whozum]

Have you heard of the Parallel Axis Theorem?

 

[Tide]

Did you learn about the parallel axis theorem?

 

[whozum]

hahahahaha

 

[Tide]

ECHO, Echo, echo! ;)

 

[ViewtifulBeau]

well thanks for the quick relpies, ummm yeah here in my book it is I = I(cm) +Mh^2

is I(cm) = 1/12 * M *L^2?
M is total mass
and h would be... distance from the center of mass?

 

[whozum]

This is true.