Moment of Inertia of rod on an axis

Click For Summary

Homework Help Overview

The discussion revolves around calculating the moment of inertia for a thin, uniform rod, first about an axis at its center and then about an axis perpendicular to the plane of the rod when bent into a V-shape. The problem involves understanding the implications of geometry on moment of inertia calculations.

Discussion Character

  • Mathematical reasoning, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the moment of inertia formula for a rod and its application in two scenarios: the straight rod and the bent rod. There are attempts to clarify the correct use of variables in the formulas and the implications of bending the rod on its moment of inertia.

Discussion Status

The discussion is ongoing, with participants questioning calculations and assumptions made regarding the mass distribution and the application of formulas. Some participants have pointed out potential errors in the calculations and the need for clarification on the relationship between the two parts of the problem.

Contextual Notes

There is confusion regarding the use of terms like "radius" versus "length" in the context of the moment of inertia formula. Additionally, participants are exploring how the bending of the rod affects the overall mass distribution and moment of inertia.

David112234
Messages
105
Reaction score
3

Homework Statement


You are a project manager for a manufacturing company. One of the machine parts on the assembly line is a thin, uniform rod that is
60.0 cm long and has mass 0.700 kg .

1What is the moment of inertia of this rod for an axis at its center, perpendicular to the rod?
Express your answer with the appropriate units.

2One of your engineers has proposed to reduce the moment of inertia by bending the rod at its center into a V-shape, with a
60.0∘ angle at its vertex. What would be the moment of inertia of this bent rod about an axis perpendicular to the plane of the V at its vertex?

Homework Equations


I of rod = 1/12 * m *L2
I of rod aorund end 1/3 * m * L2

The Attempt at a Solution



mass= .7
length= 60 cm = .6 m

Ok, I got part 1 it is .021

for part 2

If the rod is bent into a v shape and rotated around its axis, it is 2 rods half the length of the original rotation around their ends so the moment of Inertia should be

1/3 * .7 * .3^2 + 1/3 * .7 * .3^2
= .2716

why is this wrong?
 
Last edited:
Physics news on Phys.org
David112234 said:
I of rod = 1/12 * m *r2
r is the length of the rod, not the radius. (Radius of what?)
 
Doc Al said:
r is the length of the rod, not the radius. (Radius of what?)

I am use to doing moment of Inertia of discs and circle so I write radius out of habit, it is supposed to be L instead L instead of R, regardless when any point on the disc rotates it forms a disc.

but my mistake was diving by 2, it should be the whole length, though i do not understand why, the moment of inertia for a single point is mr^2 as it rotates on a disc
 
David112234 said:
1/3 * .7 * .3^2 + 1/3 * .7 * .3^2
So the whole mass is now 1.4?
Anyway, I don't see how you got .2716 from the above expression. I get .042.
 
David112234 said:
1/3 * .7 * .3^2 + 1/3 * .7 * .3^2
= .2716

why is this wrong?
Sorry, I didn't see your edits. (Thankfully, haruspex is on the ball.) In addition to his comment about the calculation, in your formula you forgot to divide the mass in two.

Hint: How should the answers to each part relate?
 

Similar threads

Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
Replies
10
Views
3K
Replies
8
Views
2K
Replies
11
Views
4K
  • · Replies 28 ·
Replies
28
Views
2K
Replies
1
Views
1K